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Volgvan
3 years ago
13

Find the slope of the line through each pair of point

Mathematics
1 answer:
Rashid [163]3 years ago
4 0

The slope of the line passes through (-6, 3) and (1, 5) is \frac{2}{7}

<u>Solution:</u>

Given, two points are (- 6, 3) and (1, 5)  

We have to find the slope of a line that passes through the above given two points

Slope of a line that pass through \left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right) is given as:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

\text { Here, in our problem, } x_{1}=-6, y_{1}=3 \text { and } x_{2}=1, y_{2}=5

\text { Slope } m=\frac{5-3}{1-(-6)}=\frac{2}{1+6}=\frac{2}{7}

Hence, the slope the line that passes through the given points is \frac{2}{7}

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Answer:

see explanation

Step-by-step explanation:

The figure shown has one pair of parallel sides and is a trapezium

The area (A) of a trapezium is calculated using

A = \frac{1}{2} h(a + b)

where h is the height and a, b the length of the parallel sides

here h = 2w, a = w + 3 and b = 4w - 2, hence

A = \frac{1}{2} × 2w(w + 3 + 4w - 2)

   = w(5w + 1) = 5w² + w


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3 years ago
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simplify (x − 2)(x + 9) using the table method, and identify the resulting expression in standard form.
NeX [460]

Answer:

this should be right if not comment and I'll relook it.

FOIL Method.

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In the diagram below, GH is parallel to DE . If GH is 3 more than EH FH=10, and DE=12 find the length of EH. Figures are not nec
steposvetlana [31]

Answer: 5

Step-by-step explanation:

Since \overline{GH} \parallel \overline{DE}, by the corresponding angles theorem, \angle FGH \cong \angle FDE, \angle FHG \cong \angle FED. This means \triangle FGH \sim \triangle FDE by AA.

As corresponding sides of similar triangles are proportional,

\frac{10}{x+3}=\frac{10+x}{12}\\(10)(12)=(10+x)(x+3)\\120=x^{2}+13x+30\\x^{2}+13x-90=0\\(x+18)(x-5)=0\\x=-18, 5
However, as distance must be positive, we consider the positive solution, x=5.

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Step-by-step explanation:

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3 years ago
NEED ANSWERS QUICKLY! CORRECT ANSWER GETS BRAINLIEST
dolphi86 [110]

Answer/Step-by-step explanation:

Quotient is simply the ratio of the first numerator to the second numerator:

Let's \frac{x_1}{y}\;and\;\frac{x_2}{y} are two fractions in same terms.

Thus, \frac{x_1}{y}\div\frac{x_2}{y} {Divided by a fraction is equal to multiplied by its reciprocal}

=\frac{x_1}{y}\times\frac{y}{x_2}

Quotient is simply the quotient of their numerators.

Example could be:

\frac{2}{7}\div\frac{3}{7}

\frac{2}{7}\times\frac{7}3}

\frac{2}{3}

2 is first numerator and 3 is the second numerator.

<u><em>~lenvy~</em></u>

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