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2 years ago

Faye is 5 ft 5 in. Faye is 10 in. Shorter than her older brother. How tall is Faye’s older brother?

Mathematics

2 answers:

Lelechka [254]2 years ago

6 0

He is 6 ft 5
Just subtract 10.

victus00 [196]2 years ago

5 0

Answer:

He's 6 ft "5"

Step-by-step explanation:

Added 10

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The figure shows the design of a greenhouse with a rectangular floor. The front and back sides of the greenhouse are semicircles

Ksju [112]

9514 1404 393

Answer:

96 cubic feet

Step-by-step explanation:

A volume that is 16 ft by 18 ft by 1/3 ft will be ...

V = LWH

V = (16 ft)(18 ft)(1/3 ft) = 96 ft³

96 cubic feet of concrete are needed.

7 0

3 years ago

Simplify the expression 9m-7m+2m

tatuchka [14]

Simplify step-by-step.

9m−7m+2m

=9m+−7m+2m

Combine Like Terms:

=9m+−7m+2m

=(9m+−7m+2m)

=4m

4 0

2 years ago

Four students were asked to write an expression which has terms that have a greatest common factor of 8c. The expressions provid

wel

Answer:

Wyatt wrote the correct expression

Step-by-step explanation:

Here we are to evaluate which of the students wrote an expression with the highest common factor being 8c

For Tanya; 32c + 16c; 16c( 2 + 1); This is wrong as the highest common factor is 16c

For Wyatt, we have 8c - 48cd; factorizing, we have 8c(1-6cd); This is correct

For Xavier we have 36c-24c; 8 is not a factor of 36, so it won’t work

For Yang 8c + 40; 8(c+ 5); what we are trying to look for is 8c and not 8 so this is wrong also

3 0

3 years ago

Read 2 more answers

Determine the formula for the nth term of the sequence:<br>-2,1,7,25,79,...

rodikova [14]

A plausible guess might be that the sequence is formed by a degree-4* polynomial,

$x_n = a n^4 + b n^3 + c n^2 + d n + e$

From the given known values of the sequence, we have

$\begin{cases}a+b+c+d+e = -2 \\ 16 a + 8 b + 4 c + 2 d + e = 1 \\ 81 a + 27 b + 9 c + 3 d + e = 7 \\ 256 a + 64 b + 16 c + 4 d + e = 25 \\ 625 a + 125 b + 25 c + 5 d + e = 79\end{cases}$

Solving the system yields coefficients

$a=\dfrac58, b=-\dfrac{19}4, c=\dfrac{115}8, d = -\dfrac{65}4, e=4$

so that the n-th term in the sequence might be

$\displaystyle x_n = \boxed{\frac{5 n^4}{8}-\frac{19 n^3}{4}+\frac{115 n^2}{8}-\frac{65 n}{4}+4}$

Then the next few terms in the sequence could very well be

$\{-2, 1, 7, 25, 79, 208, 466, 922, 1660, 2779, \ldots\}$

It would be much easier to confirm this had the given sequence provided just one more term...

* Why degree-4? This rests on the assumption that the higher-order forward differences of $\{x_n\}$ eventually form a constant sequence. But we only have enough information to find one term in the sequence of 4th-order differences. Denote the k-th-order forward differences of $\{x_n\}$ by $\Delta^{k}\{x_n\}$ . Then

• 1st-order differences:

$\Delta\{x_n\} = \{1-(-2), 7-1, 25-7, 79-25,\ldots\} = \{3,6,18,54,\ldots\}$

• 2nd-order differences:

$\Delta^2\{x_n\} = \{6-3,18-6,54-18,\ldots\} = \{3,12,36,\ldots\}$

• 3rd-order differences:

$\Delta^3\{x_n\} = \{12-3, 36-12,\ldots\} = \{9,24,\ldots\}$

• 4th-order differences:

$\Delta^4\{x_n\} = \{24-9,\ldots\} = \{15,\ldots\}$

From here I made the assumption that $\Delta^4\{x_n\}$ is the constant sequence {15, 15, 15, …}. This implies $\Delta^3\{x_n\}$ forms an arithmetic/linear sequence, which implies $\Delta^2\{x_n\}$ forms a quadratic sequence, and so on up $\{x_n\}$ forming a quartic sequence. Then we can use the method of undetermined coefficients to find it.