I NEED HELP NOW ON PROBABILITY PART 1!!!!!

Mathematics

1 answer:

miv72 [106K]4 years ago

5 0

Principle: divide the correct possibilities by the total nr. of possibilities to find the probability.

6. P(green) = 5 / (7+5+6) = 5/18
7. P(red) = 6 / 18 = 1/3
8. P(not green) = P(red | blue) = (6+7)/18 = 13/18

9. P(HH) = 5/25 = 1/5
10. P(HT) = 16/25
11. P(NOT TT) = P(HH | HT) = (5+16)/25 = 21/25
12. P(HH | TT) = (5+4)/25 = 9/25

13. P(5) = 1/6. P(H) = 1/2. P(5 & H) = 1/6*1/2 = 1/12. If you draw all the possibilities, you'll find there are 12. One of them is 5 & Heads.

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A food company sells salmon to various customers. The mean weight of the salmon is 37 lb with a standard deviation of 2 lbs. The

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Answer:

The standard deviation for the mean weigth of Salmon is 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount order stores.

Step-by-step explanation:

The mean sample of the sum of n random variables is

$\overline{X} = \frac{X_1+X_2+...+X_n}{n}$

If $X_1, ..., X_n$ are indentically distributed and independent, like in the situation of the problem, then the variance of $X_1 + .... + X_n$ will be the sum of the variances, in other words, it will be n times the variance of $X_1$ .

However if we multiply this mean by 1/n (in other words, divide by n), then we have to divide the variance by 1/n², thus $\overkine{X} = \frac{V(X_1)}{n}$ and as a result, the standard deviation of $\overline{X}$ is the standard deviation of $X_1$ divided by $\sqrt{n}$ .

Since the standard deviation of the weigth of a Salmon is 2 lbs, then the standard deviations for the mean weigth will be:

Restaurants: We have boxes with 9 salmon each, so it will be $\frac{2}{\sqrt{9}} = \frac{2}{3}$
Grocery stores: Each carton has 49 salmon, thus the standard deviation is $\frac{2}{\sqrt{49}} = \frac{2}{7}$
Discount outlet stores: Each pallet has 64 salmon, as a result, the standard deviation is $\frac{2}{\sqrt{64}} = \frac{1}{4}$

We conclude that de standard deivation of the mean weigth of salmon of the types of shipment given is: 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount outlet stores.

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3 years ago

Find the absolute maximum value for the function f(x) = x^2 − 4, on the interval [–3, 0) U (0, 2].

Andreyy89

Answer:

Step-by-step explanation:

The function $y=x^2 -4$ is