When we partition a number line from 0 to 1 into six, each segment has a length of 1/6 and the segments are:
1/6. 2/6. 3/6, 4/6, 5/6 , 6/6
Breaking 2/6 into 4 equal parts, we get each part equal to 1/12
Answer:
There is 18% left of the pie.
Step-by-step explanation:
There is only 100% of a pie. If she at 82% then there is 18% left. 100-82=18
Answer:
211
Step-by-step explanation:
As the statement indicates that on each of the 22 work days of the month the employees of the company received a communication and 4642 communications were sent, to be able to determine the number of employees that the company have, you have to divide the number of communications by the number of days:
4642/22= 211
The company has 211 employees.
Answer:
The value is
Step-by-step explanation:
From the question we are told that
The sample mean is 
The sample size is n = 25
The standard deviation is 
Given that the sample size is not large enough i.e n< 30 we will make use of the student t distribution table
From the question we are told the confidence level is 99.7% , hence the level of significance is
=>
Generally the degree of freedom is 
=> 
=>
Generally from the student t distribution table the critical value of
at a degree of freedom of
is
Generally the margin of error is mathematically represented as
=>
=>
Gnerally the upper control chart limit for 99.7% confidence is mathematically represented as

=>
=>

Step-by-step explanation:
Given polynomials are:

Both polynomials have to be multiplied. We will use distributive property for the said purpose
So,

Combining alike terms

Hence,

Keywords: Polynomials, Multiplication
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