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2 years ago

The function fx) is graphed below.

Mathematics

1 answer:

Shtirlitz [24]2 years ago

3 0

Answer:

D. 2

Step-by-step explanation:

following the graph you can see that -2 on the x line comes across to 2 in y line

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sarah competes in a long jump competion. her first jump is 4.25m. her best jump is 12% more than this. however, her best jump is

maxonik [38]

Best jump=4.25+0.12(4.25)=4.76
best jump=75% of winning jump
Winning jump=4.76/75×100=6.35m

5 0

2 years ago

Eduardo has to make a 10 minute video of his test corrections for his Algebra 2 teacher in order to be eligible to retest. His t

shutvik [7]

Answer:

7 ≤ v ≤ 13

Step-by-step explanation:

Length of video required must be within 10 minutes

Submitted length of video must be with 3 minutes of the 10 minutes video

To create an absolute value inequality :

Let v = the range of value for which the required video will be :

|v - 10| = ±3

Lower boundary :

|v - 10| = - 3

v = - 3 + 10

v = 7

Upper boundary :

|v - 10| = 3

v = 3 + 10

v = 13

Hence,

7 ≤ v ≤ 13

4 0

3 years ago

What is the true solution to 2In e sqrt in 5x = 2 In 15?

swat32

Answer:

Step-by-step explanation:

I have attached the work to your problem.

Please see the attachment below.

I hope this helps!

3 0

2 years ago

F(x) = |3x-4| give the domain and range

gulaghasi [49]

Answer:

Domain: -∞≤x≤∞

Range: 0≤F(x)≤∞

Step-by-step explanation:

The x variable can take any value.

In the case of F(x), the function only can take positive values, due to the absolute value function, and the function does not have any other restriction.

3 0

2 years ago

The park and movie theater are 3.4 inches apart on a map. If the map has a scale of 0.25 inch = 5 miles, find the actual distanc

lianna [129]

The actual distance between park and movie theater is 68 miles, if the park and movie theater are 3.4 inches apart on a map and the map has a scale of 0.25 inch = 5 miles.

Step-by-step explanation:

The given is,

Park and movie theater are 3.4 inches apart

Map has a scale of 0.25 inch = 5 miles

Step:1

Formula to calculate the number of scales for distance between park and theater,

$= \frac{Distance in map}{Scale value of map}$

$= \frac{3.4}{0.25}$

= 13.6

number of scales for distance between park and theater = 13.6

Step:2

Formula to convert distance inches to miles

$= Number of scale$ × $Equivalent value inches to miles$

= 13.6 × 5

= 68

Actual distance between park and theater = 68 miles

Result:

The actual distance between park and movie theater is 68 miles, if the park and movie theater are 3.4 inches apart on a map and the map has a scale of 0.25 inch = 5 miles.

6 0

3 years ago