"He starts both trains at the same time. Train A returns to its starting point every 12 seconds and Train B returns to its starting point every 9 seconds". Basically, what you need to do is find the least common multiple. The least common multiple of 12 and 9 is 36, so the least amount of time, in seconds, that both trains will arrive at the starting points at the same time is 36 seconds.
Answer:
52 quarters, 42 dimes
Step-by-step explanation:
Let's call the number of quarters q, and the number of dimes d.
q+d=94
0.25q+0.1d=17.20
Subtract q from both sides of the first equation to isolate d:
d=94-q
0.25q+0.1(94-q)=17.20
0.25q+9.4-0.1q=17.20
0.15q=7.8
q=52
d=94-q=42
Hope this helps!
Me lol cant do disappointed