Answer:
X = 89.92° or 90.08°
Step-by-step explanation:
The law of sines can be used to find the value of angle X:
sin(X)/26 = sin(67.38°)/24
sin(X) = (26/24)sin(67.38°) ≈ 0.99999901787
There are two values of X that have this sine:
X = arcsin(0.99999901787) ≈ 89.92°
X = 180° -arcsin(0.99999901787) ≈ 90.08°
There are two solutions: X = 89.92° or 90.08°.
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<em>Comment on the problem</em>
We suspect that the angle is supposed to be considered to be 90°. However, the given angle is reported to 2 decimal places, so we figure the requested angle should also be reported to 2 decimal places.
The lengths of the short side that correspond to the above angles are 10.03 and 9.97 units. If the short side were considered to be 10 units, the triangle would be a right triangle, and the larger acute angle would be ...
arcsin(24/26) ≈ 67.38014° . . . . rounds to 67.38°
This points up the difficulty of trying to use the Law of Sines on a triangle that is actually a right triangle.
Answer:
Follows are the solution to the given point:
Step-by-step explanation:
For option A:
In the first point let z be the number of heads which is available on the first two trails of tosses so, the equation is:
For option B:
Answer:
your answer would be b
Step-by-step explanation:
got it right
Multiply each term by 8 ( to get rid of the fractions)
we get:-
-72 = -16 - k
k = -16 + 72 = 56 answer
Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
