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4 years ago

8

You need to measure a nail in centimeters, but you only have a standard ruler. The nail measures one inch long. About how many c

entimeters is this? 0.25, 2.5, 25, 250.

2 answers:

Fed [463]4 years ago

7 0

1 inch is about 2.5 centimeters

Blizzard [7]4 years ago

4 0

An inch is 2.54 centimeters, so obviously if you round 2.54, the finger nail is 2.5 centimeters.

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20) Jermaine's goal is to eat 25 grams of protein each day. If Jermair meets his goal, how many grams of protein will he have ea

Westkost [7]

Answer:750 grams

Step-by-step explanation:

25*30=250 grams after 30 days

3 0

3 years ago

A number m is formed by writing all the prime numbers between 0 and 10 in ascending order. another number n is formed by writing

Brums [2.3K]

Answer:

(a) 1416

(b) 2 × 2 × 2 × 3 × 59

Step-by-step explanation:

The prime numbers between 0 and 10 are 2, 3, 5,7 (1 is not considered prime)
Therefore m = 2357

The square numbers between 0 and 10 are 1, 4, 9 and in descending order 9,4.1so n = 941

m - n = 2357 - 941 = 1416

Unique prime factors of 1416 are 2,3,59

1416 as a product of prime factors = 2 × 2 × 2 × 3 × 59

3 0

2 years ago

In a study to compare two different corrosion inhibitors, specimens of stainless steel were immersed for four hours in a solutio

djverab [1.8K]

Answer:

$(242-220) -1.988 \sqrt{\frac{20^2}{47} +\frac{31^2}{42}}= 10.862$

$(242-220) +1.988 \sqrt{\frac{20^2}{47} +\frac{31^2}{42}}= 33.138$

And the 95% confidence interval for the difference in the means is given by: $10.862 \leq \mu_A -\mu_B \leq 33.138$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_A = 242$ sample mean for inhibitor A

$s_A = 20$ sample standard deviation for inhibitor A

$n_A = 47$ sample size for A

$\bar X_B = 220$ sample mean for inhibitor B

$s_B = 31$ sample standard deviation for inhibitor B

$n_B = 42$ sample size for A

Solution to the problem

For this case the confidence interval for the difference of means is given by:

$(\bar X_A -\bar X_B) \pm t_{\alpha/2} \sqrt{\frac{s^2_A}{n_A} +\frac{s^2_B}{n_B}}$

The degrees of freedom are given by:

$df = n_A +n_B -2 = 47+42-2= 87$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,87)".And we see that $t_{\alpha/2}=1.988$

And replacing we got:

$(242-220) -1.988 \sqrt{\frac{20^2}{47} +\frac{31^2}{42}}= 10.862$

$(242-220) +1.988 \sqrt{\frac{20^2}{47} +\frac{31^2}{42}}= 33.138$

And the 95% confidence interval for the difference in the means is given by: $10.862 \leq \mu_A -\mu_B \leq 33.138$

4 0

3 years ago

| 5t-1 |=6 <br><br> Show all work

kipiarov [429]

Answer:

t = 1.4

Step-by-step explanation:

If you multiply 5 and 1.4 together, you get 7. Then, you do 7 - 1, and you get 6.

The inverse operation symbol things don't matter if the answer you get inside the two vertical bars is positive.

5 0

3 years ago

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PLS ANSWER ASAP AND ILL MARK BRAINLIEST!

prisoha [69]

Answer:

56.52ft³ is the answer hope this helps

3 0

3 years ago

Read 2 more answers