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nikitadnepr [17]
3 years ago
8

How to solve 54+36÷3-30​

Mathematics
2 answers:
aksik [14]3 years ago
5 0
54+36/3-30
54+12-30
66-30
36
Levart [38]3 years ago
3 0

Answer:

36

Step-by-step explanation:

just do order of operations

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PLATO
vladimir2022 [97]

Answer:

StepLet's right out the amount of times out of 20 the number 3 came out for all trials:

6/20 , 6/20, 5/20, 7/20

This probability averages at: 6/20 (6 + 6 + 5 + 7    /4 ) = 0.3

The normal probability to get one number is = 0.1666 recurring (1/6)

In relation to the normal probability the probability of getting a 3 on this die is almost double.

The experimental probability consistent with this simulation is: 6/20 (0.3)

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3 years ago
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When would a set of data be described as variable?
valina [46]
I guess when the data isn't consitant

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3 years ago
When points a and b(-3,4) are graphed in the standard (×,y)coordinate plane the mid point about will be (1,2) what will be coord
andre [41]

Answer:

The coordinates for point a will be (5,0)

Step-by-step explanation:

a=(xa,ya)=?→xa=?, ya=?

b=(-3,4)=(xb,yb)→xb=-3, yb=4

Midpoind: m=(1,2)=(xm,ym)→xm=1, ym=2

1) xm=(xa+xb)/2

Replacing the known values:

1=(xa+(-3))/2

1=(xa-3)/2

Solving for xa: Multiplying both sides of the equation by 2:

2(1)=2(xa-3)/2

2=xa-3

Adding 3 both sides of the equation:

2+3=xa-3+3

5=xa

xa=5

2) ym=(ya+yb)/2

Replacing the known values:

2=(ya+4)/2

Solving for ya: Multiplying both sides of the equation by 2:

2(2)=2(ya+4)/2

4=ya+4

Subtracting 4 both sides of the equation:

4-4=ya+4-4

0=ya

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a=(xa,ya)→a=(5,0)

6 0
3 years ago
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To find the volume of rectangular-shaped box  we will have to multiply the length by the width by the height.

Given the statements  we can determine the  length with the equation

L = h -3  where l is the length and h is the height.

the width can also be represent by the equation

w = h + 4        

The height is is h and the length is h- 3  and the width is also h+4  so the expression will be    h(h-3)(h+4)

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During a pandemic, 135 students out of 750 who attend were absent. What percent of students were absent?
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Answer:

18 percent of the students were absent

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