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3 years ago

the perimeter of a basketball court is 284 ft. the length is 40 ft longer than the width. find the dimensions of the court.

2 answers:

8 0

We know that the perimeter is the distance around an object. This is also 2 times the length + 2 times the width. We know the width would be X and the length would be 40 feet longer so it is x+40. Now we have 2 (X) + 2 (x+40)=284
Doing the distributive property you would get 2x + 2x + 80=284
add like terms to get 4x+80=284
subtract 80 from both sides to get 4x=204
divide both sides by 4 to get x=51
Width is 51 and width is 40 more than that so length is 91

mrs_skeptik [129]3 years ago

7 0

284=2x+2(x+40)
284=4x+80
204=4x
51=x
dimensions 51 ft by 91ft

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The answer is 34.05

The total distance (D) is the sum of three distances (d1, d2, and d3).

The distance formula is $d = \sqrt{(x2-x1)^{2} +(y2-y1)^{2}}$

Distance 1: Phoenix (–12, –16) to Blythe (–20, –9):
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Distance 2: Blythe (–20, –9) to Los Angeles (–33, –4):
$d2 = \sqrt{(-33-(-20))^{2} +(-4-(-9))^{2}} =\sqrt{(-33+20)^{2} +(-4+9)^{2}} \\ =\sqrt{(-13)^{2} +(5)^{2}}= \sqrt{169+25} = \sqrt{194}= 13.93$

Distance 3: Los Angeles (–33, –4) to San Francisco (–36, 5)
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