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2 years ago

Need help with this?

Mathematics

1 answer:

artcher [175]2 years ago

4 0

Alright, let's break it down to help you.

An annual budget is how much you can spend in total for that year.

Media is 6% and sales are 14% of the total annual budget. So, that means $30,000,000 is only 20%

Now, due to the reason that you have to find the total budget you need to solve that.

You need to use 5 20% to make 100% due to that reason, you would times $30,000,000 by 5 so,

$30,000,000*5= $150,000,000

The total annual budget is $150,000,000

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Step-by-step explanation:

Quotient of 18 and 2 is 9, and just take the 9 out of the next series and you will be left with 22.

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2 years ago

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3 years ago

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Please help and show all work so I can fully understand it, thanks.

seraphim [82]

Answer:

$\frac{1}{m-4}$

Step-by-step explanation:

$\frac{\frac{4m-5}{m^4 -7m^3 +12m^2}}{\frac{4m-5}{m^3 -3m^2}}$

Factor the equation:

$\frac{\frac{4m-5}{m^2(m^2 -7m+12)}}{\frac{4m-5}{m^2(m-3)}}$

$\frac{\frac{4m-5}{m^2(m-3)(m-4)}}{\frac{4m-5}{m^2(m-3)}}$

Rewrite to suit the format of multiplying two fractions. Remember, dividing two fractions is the same as multiplying the first fraction by the reciprocal of the second. A reciprocal of a fraction is when one switches the place of the numerator and the denominator, that is, the value on top (numerator), and the value on the bottom (denominator).

$\frac{4m-5}{m^2(m-3)(m-4)}*\frac{m^2(m-3)}{4m-5}$

Simplify, take out common terms that are found on both the numerator and denominator

$\frac{4m-5}{m^2(m-3)(m-4)}*\frac{m^2(m-3)}{4m-5}$

$\frac{1}{m-4}$

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2 years ago