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wolverine [178]
3 years ago
11

Evaluate 8 + 3e when e = 2. Need the Answer

Mathematics
1 answer:
alexandr402 [8]3 years ago
6 0

Answer:

The answer is 14

Step-by-step explanation:

e=2

Substitute 2 in for e

8 + 3(2)

Solve

14

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5(x-10)=30-15x<br> Ox=1<br> Ox=4<br> Ox=5<br> Ox=8
makvit [3.9K]

Answer:

x = 4

Step-by-step explanation:

5x-50=30-15x

5x +15x =30+50

20x= 80

Divide both sides of the equation by 20

x = 4

I hope it helps

7 0
3 years ago
Step 3: Solving a system of equations to make comparisons between men and women
zysi [14]

I am also not able to solve thi s question

7 0
3 years ago
Solve for t: 4n = 2(t-3)
spayn [35]
T=2n+3
considering n has no other values given
3 0
3 years ago
Find the midpoint of the segment having endpoints (0 ,1/8) and (-4/5 ,0)
kvasek [131]

Answer:

Mid point of the given end points = (\frac{-2}{5},\frac{1}{16} )

Step-by-step explanation:

Given the end points of the line segment are :

(0, \frac{1}{8}) & (\frac{-4}{5},0)

We will use the mid point formula when two points are: (x₁,y₁) & (x₂,y₂)

mid point = (\frac{x_{1} +x_{2} }{2},\frac{y_{1} +y_{2} }{2} )

now put the value of x₁ = 0

x₂ = \frac{-4}{5}

y₁ = \frac{1}{8}

y₂ = 0

mid point = (\frac{0-\frac{4}{5} }{2},\frac{\frac{1}{8}+0 }{2})

                = (\frac{-2}{5},\frac{1}{16} )

That's the final answer.

3 0
3 years ago
An airplane travels 290 km between Austin and Dallas in 1 h 15 min. What is it’s average speed?
aniked [119]

The average speed of the plane between Austin and Dallas is 232 kmph

<u>Solution:</u>

Given that,

Total distance traveled by airplane = 290 km

Time taken for travel between Austin and Dallas = 1 hour 15 minute

Let us convert the time taken to hours

\begin{array}{l}{1 \text { minute }=\frac{1}{60} \text { hours }} \\\\ {15 \text { minutes }=\frac{15}{60}=\frac{1}{4}} \\\\ {\text { 1 hour } 15 \text { minutes }=1 \frac{1}{4} \text { hours }=\frac{1 \times 4+1}{4}=\frac{5}{4} \text { hours }}\end{array}

<em><u>The average speed is given as:</u></em>

\text { Average speed }=\frac{\text { total distance }}{\text { total time taken }}

Plugging in the values, we get,

\text { Average speed }=\frac{290}{\frac{5}{4}}=\frac{290}{5} \times 4=232

Hence the average speed is 232 kmph

6 0
3 years ago
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