2.83 I believe because 8 rounded to nearest is 2+1
Let p(x)=x^3+2x^2+kx+3
On dividing p(x) by x-3, the remainder is 21. Therefore,
P(3)=21
Substituting x=3 in p(x)
P(3)=3^3 +2*(3)^2+k*3+3
=27+18+3k+3
=48+3k
We know that, p(3)=21.
So, 48+3k=21
3k=21-48
3k=-27
k=-27/3 =-9
now, p(x) =x^3+2x^2-9x-18
-2 is a factor of p(x) on inspection. Therefore, divide p(x) by x+2 to find the
zeroes of the polynomial.
On dividing, we get the factors to be, (x^2-9)(x+2)
(x^2-3^2)(x+2)
Factorizing using the identity a^2-b^2=(a+b)(a-b) we get,
(x+3)(x-3)(x+2)
Therefore, the zeroes of the polynomials are -3,+3 and -2.
Answer: 22
Step-by-step explanation:
Evaluate g + 3h - 6 when g = 10 and h = 6.
Substitute the values of g and h into the expression :
10 + 3(6) -6.......open the bracket
= 10 + 18 - 6
=28 - 6
= 22
:
Independent variable = $20
dependent variable = $0.05 cents per min
y = total month cost
x = month minutes used
y = 20 + 0.05x
I believe it’s 2 because rise/run and 14/7 = 2
