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3 years ago

SM=3x−4, and RN=9x−20. Find the value of x

Mathematics

1 answer:

Rudik [331]3 years ago

8 0

Answer:

Option (A).

Step-by-step explanation:

Given question is incomplete; find the complete question with the attachment.

In the triangle NRL,

Points P, S and M are the midpoints of the sides NR, RL and LN respectively.

Sides SM = (3x - 4), NR = (9x - 20)

By the theorem of midpoints in a triangle,

SM = $\frac{1}{2}\text{NR}$

(3x - 4) = $\frac{1}{2}(9x-20)$

6x - 8 = 9x - 20

9x - 6x = 20 - 8

3x = 12

x = 4

Therefore, Option (A) will be the answer.

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Naily [24]

Answer:

$\huge\boxed{Diameter=11cm}$

Step-by-step explanation:

Important information:

Circumference of a circle= $\pi*diameter$

Method:

To work out the diameter, we would need to divide the circumference of 34.54 by pi, which in this case is 3.14, this gives us 11cm. This is because we are simply rearanging the formula of the circumference of a circle to make the diameter the subject.

Step By Step:

1) Rearange the formula to make the diameter the subject.

$diameter=\frac{circumference}{\pi}$

2) Divide 34.54 by 3.14( $\pi$ ).

$34.54/3.14=11cm$

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