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3 years ago

7

I'm not sure what interval I would use in this data so please help!!

1 answer:

agasfer [191]3 years ago

4 0

In mathematics<span>, a (real) </span>interval<span> is a set of real numbers with the property that any number that lies between two numbers in the set is also included in the set. For example, the set of all numbers x satisfying 0 ≤ x ≤ 1 is an </span>interval<span> which contains 0 and 1, as well as all numbers between them. So this should help you solve your problem.</span>

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2 years ago

Write an expression that is equivalent to 3/4(5z+16).

Sphinxa [80]

Answer: 3.75z+12
For an equivalent expression, lets simplify the equation.

3/4(5z+16)
multiply both '5z' and '16' by 3/4
3.75z+12

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3 years ago

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Pls help me, all of this I’m sending is due by 11:59pm. And my time right now is 9:16pm. So plsss

yan [13]

Answer:

4(7y - 9)

Step-by-step explanation:

The greatest common factor you can factor out of both monomials is 4.

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3 years ago

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a pyramid whose altitude is 5ft weighs 800lbs. at what distance from its vertex must it be cut by a plane parallel to its base s

slavikrds [6]

A structure which has a square base and four triangular sides meeting at a point is called pyramid.

At distance of 3.97 feet from its vertex , pyramid is cut by plane so that the two solids of equal weight will be formed.

<u>It is assumed that weight of pyramid is proportional to its volume.</u>

So, $w = k V$ , where V is volume of original pyramid and v is volume of small pyramid and k is constant.

Let us consider that at h distance, pyramid is cut from its vertex. So a small pyramid is also formed.

Assume that base area of original pyramid is A and base of small pyramid is a.

Volume of original pyramid is, $V= \frac{1}{3} *A* 5$

So, weight of original pyramid, $W = k *(\frac{1}{3} *A* 5) = 800$

Volume of small pyramid is, $v = \frac{1}{3}* a* h$

So, weight of small pyramid, $w = k*(\frac{1}{3}* a* h)=400$

<u>Since, base and height of small pyramid and original pyramid are in proportion.</u>

So, $\frac{a}{A} = (\frac{h}{5}) ^{2}$

$a = (\frac{h}{5} )^{2}A$

Substituting value of a in equation $k*(\frac{1}{3}* a* h)=400$

So, $k*(\frac{1}{3}* \frac{h^{2} }{25}A * h)=400$

$(k*\frac{1}{3}* A*5)*\frac{1}{5} *\frac{h^{2} }{25} * h)=400$

Since, $(k *\frac{1}{3} *A* 5) = 800$ , substitute in above equation.

So, $800*\frac{h^{3} }{125}=400\\\\h^{3}=\frac{125}{2}\\\\h=\sqrt[\frac{1}{3} ]{62.5}\\\\h=3.97 feet$

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3 years ago

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Write an equation in point-slope form, if m= 3 and passes through (4, 5).

Sergio039 [100]

Answer:

y - 5 = 3(x - 4)

General Formulas and Concepts:

<u>Algebra I</u>

Point-Slope Form: y - y₁ = m(x - x₁)

x₁ - x coordinate

y₁ - y coordinate

m - slope

Step-by-step explanation:

<u>Step 1: Define</u>

Slope <em>m</em> = 3

Point (4, 5)

<u>Step 2: Write equation</u>

Point-Slope Form: y - 5 = 3(x - 4)

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3 years ago