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Travka [436]
3 years ago
13

Consider the probability that at most 93 out of 127 students will pass their college placement exams. Assume the probability tha

t a given student will pass their college placement exam is 53%. Specify whether the normal curve can be used as an approximation to the binomial probability by verifying the necessary conditions.
the answer will be in yes or no format
Mathematics
1 answer:
dezoksy [38]3 years ago
7 0

Answer:

Yes, the normal curve can be used as an approximation to the binomial probability.

Step-by-step explanation:

Let <em>X</em> = number of students that pass their college placement exam.

The probability that a given student will pass their college placement exam is, P (X) = <em>p</em> = 0.53.

A random sample of <em>n</em> = 127 students is selected.

The random variable <em>X</em> follows a Binomial distribution.

But the sample size is too large.

A Normal approximation to Binomial can be used to approximate the distribution of proportion <em>p</em>.

The conditions to be satisfied are:

  • <em>np</em> ≥ 10
  • <em>n</em>(1-<em>p</em>) ≥ 10

Check whether the conditions are satisfied as follows:

np=127\times0.53=67.31>10

n(1-p)=127\times(1-0.53)=59.69>10

Both he conditions are satisfied.

Thus, a normal curve can be used as an approximation to the binomial probability.

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nekit [7.7K]
ANSWER

The simplest form of the ratio
30:6
is

5:1


EXPLANATION

The ratio given to us is
30:6


We can divide each term in ratio by the same number.


To find the ratio in the simplest form we divide the terms in the ratio by their highest common factor, which is
6.


This implies that,

30:6 =  \frac{30}{6} : \frac{6}{6}


We simplify this to obtain,



30:6 = 5: 1


The correct answer is C.



Alternatively,


30:6 =   \frac{30}{6}


30:6 =   \frac{5}{1}


This implies that,


30:6 =   5:1



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Viefleur [7K]
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Answer:

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