Answer:
2nd and 4th ones
Explanation:
More sugar dissolves in water than salt
more aspirin dissolves in water than CO2 ...but less aspirin than table salt (NaCl)
The coefficients of the substances give you the ratio of the number of moles.
The 4 before the H2O and the 5 before the HCl tell you that for every 5 moles of HCl created, 4 moles of H2O had to react.
Therefore:
can be used to find the moles of H2O that react.
Answer:
The process describes the source of energy of the Sun such that it shines as a result of nuclear fusion of hydrogen taking place.
Explanation:
The Sun generates energy by hydrogen within the Sun undergoing nuclear fusion to form helium.
Nuclear fusion reaction involves combining of two or more atomic nuclei to produce one or more completely different atomic nuclei as well as protons or neutrons, with a loss or gain of mass and the release or absorption of energy.
The process whereby four hydrogen atoms combine to form one helium atom with a mass deficit, which is accounted for by the release of energy, result in the high intense light of the Sun.
Aphelion in miles =94290301
Perihelion in miles = 91200281
Explanation:
To convert km in mile we use the multiply the distance in km with 0.62, because there are 0.62 miles in 1 km.
Aphelion in miles = aphelion in km × 0.62
Aphelion in miles = 152081132 × 0.62
Aphelion in miles =94290301
Perihelion in miles = perihelion in km × 0.62
Perihelion in miles = 147097229 × 0.62
Perihelion in miles = 91200281
Learn more about:
conversion of units
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Answer: The correct option is, (C) 0.53
Explanation:
The given chemical reaction is:
The rate of the reaction for disappearance of A and formation of C is given as:
![\text{Rate of disappearance of }A=-\frac{1}{9}\times \frac{\Delta [A]}{\Delta t}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20of%20disappearance%20of%20%7DA%3D-%5Cfrac%7B1%7D%7B9%7D%5Ctimes%20%5Cfrac%7B%5CDelta%20%5BA%5D%7D%7B%5CDelta%20t%7D)
Or,
![\text{Rate of formation of }C=+\frac{1}{5}\times \frac{\Delta [C]}{\Delta t}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20of%20formation%20of%20%7DC%3D%2B%5Cfrac%7B1%7D%7B5%7D%5Ctimes%20%5Cfrac%7B%5CDelta%20%5BC%5D%7D%7B%5CDelta%20t%7D)
where,
= change in concentration of C = 1.33 M
= change in time = 4.5 min
Putting values in above equation, we get:
![\frac{1}{9}\times \frac{\Delta [A]}{\Delta t}=\frac{1}{5}\times \frac{\Delta [C]}{\Delta t}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B9%7D%5Ctimes%20%5Cfrac%7B%5CDelta%20%5BA%5D%7D%7B%5CDelta%20t%7D%3D%5Cfrac%7B1%7D%7B5%7D%5Ctimes%20%5Cfrac%7B%5CDelta%20%5BC%5D%7D%7B%5CDelta%20t%7D)
![\frac{\Delta [A]}{\Delta t}=\frac{9}{5}\times \frac{\Delta [C]}{\Delta t}](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20%5BA%5D%7D%7B%5CDelta%20t%7D%3D%5Cfrac%7B9%7D%7B5%7D%5Ctimes%20%5Cfrac%7B%5CDelta%20%5BC%5D%7D%7B%5CDelta%20t%7D)
![\frac{\Delta [A]}{\Delta t}=\frac{9}{5}\times \frac{1.33M}{4.5min}](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20%5BA%5D%7D%7B%5CDelta%20t%7D%3D%5Cfrac%7B9%7D%7B5%7D%5Ctimes%20%5Cfrac%7B1.33M%7D%7B4.5min%7D)
![\frac{\Delta [A]}{\Delta t}=0.53M/min](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20%5BA%5D%7D%7B%5CDelta%20t%7D%3D0.53M%2Fmin)
Thus, the decrease in A during this time interval is, 0.53
