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sineoko [7]
3 years ago
8

The balanced chemical equation for the reaction between PCl5 and water is given below. If 3.45 moles of HCl are produced, how ma

ny moles of water reacted?
PCl5 + 4H2O -> H3PO4 + 5HCl
Chemistry
1 answer:
enyata [817]3 years ago
6 0
The coefficients of the substances give you the ratio of the number of moles.
The 4 before the H2O and the 5 before the HCl tell you that for every 5 moles of HCl created, 4 moles of H2O had to react.

Therefore:
(3.45mol HCl)(\frac{4 mol H2O}{5 mol HCl})
can be used to find the moles of H2O that react.

(3.45mol HCl)(\frac{4 mol H2O}{5 mol HCl}) = 2.76 mol H20
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gayaneshka [121]

<u>Answer:</u>

<u>For a:</u> Work done for the given reaction is 2477.572 J.

<u>For b:</u> Work done for the given reaction is 0 J

<u>Explanation:</u>

To calculate the work done for the reaction, we use the equation:

W=-P\Delta V

Ideal gas equation follows:

PV=nRT

Relating both the above equations, we get:

W=-\Delta n_gRT     ......(1)

where,

\Delta n_g = difference in number of moles of products and reactants = n_g_{(products)}-n_g_{(reactants)}

R = Gas constant = 8.314 J/K.mol

T = temperature = 25^oC=[273+25]K=298K

  • <u>For a:</u>

The chemical reaction follows:

4HCl(g)+O_2(g)\rightarrow 2Cl_2(g)+2H_2O(g)

\Delta n_g=4-5=-1

Putting values in equation 1, we get:

W=-(-1mol)\times (8.314J/K.mol)\times 298K=2477.572J

Hence, work done for the given reaction is 2477.572 J.

  • <u>For b:</u>

The chemical reaction follows:

2NO(g)\rightarrow N_2(g)+O_2(g)

\Delta n_g=2-2=0

Putting values in equation 1, we get:

W=-(0mol)\times (8.314J/K.mol)\times 298K=0J

Hence, work done for the given reaction is 0 J.

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In the reaction of aluminum hydroxide and caldium nitrate, how many grams of calcium hydroxide will be formed if 12.55 g of alum
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Answer:

17.76g

Explanation:

We need to write a balanced chemical equation for the reaction:

2Al(OH)3 + 3Ca(NO3)2 ——> 3Ca(OH)2 + 2Al(NO3)3

In the reaction above, it can be seen that 2 moles of aluminum hydroxide yielded 3 moles of calcium hydroxide. This is the theoretical viewpoint.

Now we need to know what actually happened. We need to calculate the actual number of moles of aluminum hydroxide reacted l. We can get this by dividing the mass by the molar mass.

The molar mass of aluminum hydroxide is 27+ 3( 16+1)

= 27 + 51 = 78g/mol

The number of moles is thus: 12.55/78 = 0.16 moles

Now if 2 moles of aluminum hydroxide gave 3 moles of calcium hydroxide, 0.16moles will give : (0.16*3)/2 = 0.24moles

Now we can calculate the mass of calcium hydroxide formed. The mass of calcium hydroxide formed is the number of moles multiplied by the molar mass.

The molar mass of calcium hydroxide is; 40 + 2(17) = 74g/mol

The mass is thus =74 * 0.24 = 17.76g

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