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abruzzese [7]
4 years ago
13

Grab 2/3 gallon of yellow paint and 1/4 gallon of white paint to paint his dresser how many gallons of paint did you use

Mathematics
2 answers:
Brums [2.3K]4 years ago
5 0
2/3 + 1/4 = 8/12 + 3/12 =11/12
inn [45]4 years ago
3 0
You will get 11/12 of paint
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X + y = 12
pantera1 [17]

Answer:

Step-by-step explanation:

-22

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3 years ago
Someone help,please.I don't understand very well.
Setler79 [48]
You just add THAM All up
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3 years ago
What is the volume of a cone with the given dimensions?
yuradex [85]
B. 102.57 cu. cm is the answer Solution: V=πr^2h The diameter is 14. To find the radius you divide the radius by 2 which is equal to 7. [Radius is 2 times diameter] V= 3.14×7×7×2 V= 102.57
8 0
3 years ago
Read 2 more answers
Can someone please help……
Arada [10]

Answer:

first option

Step-by-step explanation:

I don't know how to explain

3 0
3 years ago
38. Evaluate f (3x +4y)dx + (2x --3y)dy where C, a circle of radius two with center at the origin of the xy
lina2011 [118]

It looks like the integral is

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy

where <em>C</em> is the circle of radius 2 centered at the origin.

You can compute the line integral directly by parameterizing <em>C</em>. Let <em>x</em> = 2 cos(<em>t</em> ) and <em>y</em> = 2 sin(<em>t</em> ), with 0 ≤ <em>t</em> ≤ 2<em>π</em>. Then

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy = \int_0^{2\pi} \left((3x(t)+4y(t))\dfrac{\mathrm dx}{\mathrm dt} + (2x(t)-3y(t))\frac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt \\\\ = \int_0^{2\pi} \big((6\cos(t)+8\sin(t))(-2\sin(t)) + (4\cos(t)-6\sin(t))(2\cos(t))\big)\,\mathrm dt \\\\ = \int_0^{2\pi} (12\cos^2(t)-12\sin^2(t)-24\cos(t)\sin(t)-4)\,\mathrm dt \\\\ = 4 \int_0^{2\pi} (3\cos(2t)-3\sin(2t)-1)\,\mathrm dt = \boxed{-8\pi}

Another way to do this is by applying Green's theorem. The integrand doesn't have any singularities on <em>C</em> nor in the region bounded by <em>C</em>, so

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy = \iint_D\frac{\partial(2x-3y)}{\partial x}-\frac{\partial(3x+4y)}{\partial y}\,\mathrm dx\,\mathrm dy = -2\iint_D\mathrm dx\,\mathrm dy

where <em>D</em> is the interior of <em>C</em>, i.e. the disk with radius 2 centered at the origin. But this integral is simply -2 times the area of the disk, so we get the same result: -2\times \pi\times2^2 = -8\pi.

3 0
3 years ago
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