a the side lengths must be = but only opposite angles must be = it COULD be a square but is could be many other things.
We need to figure out how much string would be left, after taking away the first two pieces.
We know that the first piece is 20 inches long, so we can say that there is 52-20 inches left, or 32 inches.
The second piece is between 12 and 18 inches, meaning that there would be between 32-12 and 32-18 inches left for the third piece, or 20 and 14 inches. This means that the third piece would be at least 14 inches long, but no more than 20, since we don’t have more string than that (20+12+20=52, and 20+14+18=52)
So we can say that x is greater or equal to 14, but less than or equal to 20, or:
14<=x<=20 (“<=“ is written like a normal “<“ sign with a line _ right under it)
Answer:
should be -29.29 %
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
Firstly, this is the pythagoreans theorem a^2+b^2=c^2
Now that we know that, we will solve for x.
(x+2)^2+x^2=100 ( The 100 is just 10 squared )
Finally, you solve for x and get 6.
Answer: 1014.2
Step-by-step explanation: you look to the right of 1 and if it is 5 or greater you round up. If it is 4 or less you keep it the same number as it is.
