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guajiro [1.7K]
3 years ago
14

Draw a right triangle with side lengths of 3, 4, and 5 units. Please show a picture.

Mathematics
1 answer:
Arada [10]3 years ago
7 0

Answer:

https://www.google.com/url?sa=i&source=imgres&cd=&ved=2ahUKEwig0N2PrePnAhVLQq0KHQsCAi0QjRx6BAgBEAQ&url=http%3A%2F%2Fmathworld.wolfram.com%2F345Triangle.html&psig=AOvVaw3V2l2h-p2cQ4XBgk2MthwI&ust=1582398823143518

Step-by-step explanation:

click it

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6(x+1)=24 solution to equation
Vladimir79 [104]
6(x+1)=24
6x+6=24
6x=24-6
6x=18
6x/6=18/6
x=3
5 0
3 years ago
Hahaha I need help again please
attashe74 [19]
It could be 2+1 beacuse it says there are twice as many
5 0
3 years ago
Y=–6x+2<br> –12x – 2y=–4<br> How many solutions does this linear system have?
DerKrebs [107]

The linear equation y = -6x + 2; -12x - 2y = -4 has no solution

<h3>Linear equation</h3>

y = -6x + 2

-12x - 2y = -4

  • Substitute y = -6x + 2 into (2)

-12x - 2y = -4

-12x - 2(-6x + 2) = -4

-12x + 12x -4 = -4

-12x + 12x = - 4 + 4

0 = 0

  • Solve for x

y = -6x + 2

y - 2 = -6x

x = (y - 2) / -6

  • Substitute into (2)

-12x - 2y = -4

-12(y- 2)/ 6 - 2y = -4

(-12y + 24) / 6 - 2y = -4

-2y + 4 - 2y = 4

0 = 0

Learn more about linear equation:

brainly.com/question/4074386

#SPJ1

3 0
2 years ago
Which could a translation result in? Select all that apply. a figure getting smaller a figure moving up a figure flipping upside
makkiz [27]

Answer:

A figure moving up, a figure moving left, and a figure moving down.

Step-by-step explanation:

Translations are just moving things around in any direction.

8 0
3 years ago
Read 2 more answers
A closet contains n pairs of shoes. If 2r shoes are chosen at random, (where 2r &lt; n), what is the probability that there will
Pie
We are choosing 2
2
r
shoes. How many ways are there to avoid a pair? The pairs represented in our sample can be chosen in (2)
(
n
2
r
)
ways. From each chosen pair, we can choose the left shoe or the right shoe. There are 22
2
2
r
ways to do this. So of the (22)
(
2
n
2
r
)
equally likely ways to choose 2
2
r
shoes, (2)22
(
n
2
r
)
2
2
r
are "favourable."

Another way: A perhaps more natural way to attack the problem is to imagine choosing the shoes one at a time. The probability that the second shoe chosen does not match the first is 2−22−1
2
n
−
2
2
n
−
1
. Given that this has happened, the probability the next shoe does not match either of the first two is 2−42−2
2
n
−
4
2
n
−
2
. Given that there is no match so far, the probability the next shoe does not match any of the first three is 2−62−3
2
n
−
6
2
n
−
3
. Continue. We get a product, which looks a little nicer if we start it with the term 22
2
n
2
n
. So an answer is
22⋅2−22−1⋅2−42−2⋅2−62−3⋯2−4+22−2+1.
2
n
2
n
⋅
2
n
−
2
2
n
−
1
⋅
2
n
−
4
2
n
−
2
⋅
2
n
−
6
2
n
−
3
⋯
2
n
−
4
r
+
2
2
n
−
2
r
+
1
.
This can be expressed more compactly in various ways.
4 0
3 years ago
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