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guajiro [1.7K]
2 years ago
14

Draw a right triangle with side lengths of 3, 4, and 5 units. Please show a picture.

Mathematics
1 answer:
Arada [10]2 years ago
7 0

Answer:

https://www.google.com/url?sa=i&source=imgres&cd=&ved=2ahUKEwig0N2PrePnAhVLQq0KHQsCAi0QjRx6BAgBEAQ&url=http%3A%2F%2Fmathworld.wolfram.com%2F345Triangle.html&psig=AOvVaw3V2l2h-p2cQ4XBgk2MthwI&ust=1582398823143518

Step-by-step explanation:

click it

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Graph the inequality and check the solution.
denis-greek [22]

Answer:

B,C,E

Step-by-step explanation:

did the assignment on Edge 2020

B. draw an open circle at 100

C. shade all numbers to the right of 100

E. 150 is shaded, so substitute 150 in for the variable to check the graph of the solution

5 0
2 years ago
What is the value of x? enter your answer in the box. x =
leonid [27]

Answer:

Step-by-step explanation:

Sum of all angles of triangle = 180

39 + 102 + x = 180

         141 + x = 180

Subtract 141 from both sides

                 x = 180 - 141

                 x = 39

4 0
2 years ago
Select the expression that is equivalent to (picture)
seraphim [82]
The answer to this question is x^(rt + s) since (x^r)^t becomes x^(rt) by the exponent power of a power property. Then multiplying powers of the same base results in the exponents being summed.
6 0
3 years ago
Nasir and Seif began with an equal number of Skittles. Nasir ate 10 Skittles, and Seif ate 6. Now the ratio of Nasir's Skittles
Finger [1]
X=Amount of skittles at the start.
Nasir ate 10 skittles and Seif ate 6 skittles so the number of skittles they had(x) - how many they both ate equals : 2/3;

(x-10)/(x-6)=2/3
3(x-10)=2(x-6)
3x-30=2x-12
x-30=-12
x=18

They each started with 18 skilttles.
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=tan20%2B4sin20%3D%5Csqrt%7B3%7D" id="TexFormula1" title="tan20+4sin20=\sqrt{3}" alt="tan20+4si
zepelin [54]

tan( 20 ) + 4 Sin( 20 ) =

( Sin( 20 ) / Cos( 20 ) ) + 4 Sin( 20 ) =

Sin( 20 ) + 4 Sin( 20 ).Cos( 20 ) / Cos( 20 ) =

Sin( 20 ) + 2 × 2 Sin(20).Cos(20)/ Cos(20) =

Sin( 20 ) + 2 × Sin( 40 ) / Cos( 20 ) =

Sin( 20 ) + 2Sin( 40 ) / Cos( 20 ) =

Sin( 20 ) + 2Cos( 50 ) / Cos ( 20 ) =

Sin( 20 ) + 2Cos( 20 + 30 ) / Cos( 20 ) =

________________________________

2 × Cos( 30 + 20 ) =

2 × [ Cos(30).Cos(20) - Sin(30).Sin(20) ] =

2 × [ √3/2 × Cos(20) - 1/2 × Sin(20) ] =

√3 Cos(20) - Sin(20)

_________________________________

Sin( 20 ) + 2Cos ( 20 + 30 ) / Cos( 20 ) =

Sin( 20 ) + √3 Cos(20) - Sin(20) / Cos(20) =

Sin(20) - Sin(20) + √3 Cos(20) / Cos(20) =

0 + √3 Cos(20) / Cos(20) =

√3 Cos(20) / Cos(20) =

Cos(20) simplifies from the numerator and denominator of fraction

√3 × 1 / 1 =

√3

And we're done ....

5 0
2 years ago
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