Find the zeros<span> of Function (</span>x)= (x+3)^2(x-5)^6 and state the multiplicity. ... (x--5)^6<span> = 0=> </span>x--5<span>= 0 => </span>x<span> = </span>5<span>. Therefore real </span>zero's of the function<span> are --</span>3<span>,5.</span><span />
Answer:
The answer is (d) ⇒ eccentricity = 6 , hyperbola , directrix x = 3/2
Step-by-step explanation:
∵ r = ek/(1 ± ecosФ)
∵ r = 9/(1 + 6cosФ)
∴ e = 6 ⇒ eccentricity = 6
∵ e > 1
∴ The conic is hyperbola
∵ ek = 9
∴ k = 9/6 = 3/2
∴ The directrix x = 3/2
Answer:
P(A) = 0.57 (to the nearest hundredth)
Step-by-step explanation:
There are 7 letters in total
4 of them are the letter A
⇒ P(A) = 4/7
= 0.5714285714...
= 0.57 (to the nearest hundredth)
Answer: A(b+c)
Step-by-step explanation: Since you're multiplying A and A you would add the B+C
