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2 years ago

Solve v pls 3|v - 3|=9

Mathematics

1 answer:

Ganezh [65]2 years ago

7 0

The answer is 0

Let's solve your equation step-by-step.

3(|v−3|)=9

Step 1: Divide both sides by 3.

3(|v−3|)3=93

|v−3|=3

Step 2: Solve Absolute Value.

|v−3|=3

We know either v−3=3orv−3=−3

v−3=3(Possibility 1)

v−3+3=3+3(Add 3 to both sides)

v=6

v−3=−3(Possibility 2)

v−3+3=−3+3(Add 3 to both sides)

v=0

Answer:

v=6 or v=0

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The value of n for (a) n=425. (b) n=0.

Step-by-step explanation:

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(a) For Trapezoidal Rule : Composite error is,

$E_T=-\frac{(b-a)^3}{12n^2}f''(x_m)$

Where, f''(x_m)=greatest value of |f''(x)|= |4|=4, a=-3, b=3. Therefore to find the minimum number of subinterval,

$|E_T|\leq | \frac{(b-a)^3}{12n^2}f''(x)|$ |

$\leq \frac{4(-3-3)^3}{12n^2}$

$=\frac{72}{n^2}$

According to the question, we must choose n such that,

$\frac{72}{n^2}$

$\implies n>424.2640686$

So we can take n=425.

(b) For Simpson 1/3 rule : Composite error is,

$E_S=-\frac{(b-a)^5}{180n^4}f^{(iv)}(x_m)$

where, $f^{(x_m)}=\textit{greatest value of} |f^{(iv)}(x)|$

In this problem $f^{(iv)}(x)=0$ , so that,

$|E_S|\leq 0$

that is there exist no error. So n=0.

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2 years ago

Solve v pls 3|v - 3|=9​

Solve v pls 3|v - 3|=9