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3 years ago

Need help asap x=4 and y= -9 2xy+15x

Mathematics

2 answers:

ohaa [14]3 years ago

8 0

Answer:

Step-by-step explanation:

2xy+15x

Let x=4 and y= -9

2(-4)(-9) + 15(-4)

Multiply

72 -60

Subtract

Mariana [72]3 years ago

6 0

Answer:

-12

Step-by-step explanation:

2(4)(-9)+15(4) is what it should look like.

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You are using extension ladders to paint a chimney that is 33 feet tall. The length of an extension ladder ranges in 1 foot inte

Alexus [3.1K]

Answer:

The ladder has to be 65 feet long to the nearest foot.

Step-by-step explanation:

The height of the chimney from the ground is the sum of the height of the wall and the height of the chimney.

Therefore, the height of the chimney from the ground = (30 + 33) = 63 feet.

Now, the ladder makes a right triangle with the ground and the chimney and the ladder makes an angle of 75.5° with the ground.

Therefore, using trigonometry we can write,

$\sin 75.5 ^{\circ} = \frac{\textrm {The height of the chimney from the ground}}{\textrm {Length of the ladder}} = \frac{63}{\textrm {Length of the ladder}}$

⇒ The length of the ladder = 65 feet.

Hence, the ladder has to be 65 feet long to the nearest foot. (Answer)

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3 years ago

What is the solution of x + <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D" id="TexFormula1" title="\frac{1}{5}" alt="\

givi [52]

Your answer would be A.1

6 0

3 years ago

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Need the answer for the bottom plz

Katena32 [7]

Answer:

16 weeks

Step-by-step explanation:

161+27x>580

solve for x

27x>580-161

27x>419

x=419/27

x=15.52

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3 years ago

Will mark Brainlest please answer. find the value of a,b. <br>,p,q from the equal order pairs

NARA [144]

Step-by-step explanation:

<h3>Question-1:</h3>

by order pair we obtain:

$\displaystyle \begin{cases} \displaystyle 3p = 2p - 1 \dots \dots i\\2q - p = 1 \dots \dots ii\end{cases}$

cancel 2p from the i equation to get a certain value of p:

$\displaystyle \begin{cases} \displaystyle p = - 1 \\2q - p = 1 \end{cases}$

now substitute the value of p to the second equation:

$\displaystyle \begin{cases} \displaystyle p = - 1 \\2q - ( - 1) = 1 \end{cases}$

simplify parentheses:

$\displaystyle \begin{cases} \displaystyle p = - 1 \\2q + 1= 1 \end{cases}$

cancel 1 from both sides:

$\displaystyle \begin{cases} \displaystyle p = - 1 \\2q = 0\end{cases}$

divide both sides by 2:

$\displaystyle \begin{cases} \displaystyle p = - 1 \\q = 0\end{cases}$

<h3>question-2:</h3>

by order pair we obtain:

$\displaystyle \begin{cases} \displaystyle 2x - y= 3 \dots \dots i\\3y= x + y \dots \dots ii\end{cases}$

cancel out y from the second equation:

$\displaystyle \begin{cases} \displaystyle 2x - y= 3 \dots \dots i\\ x = 2y \dots \dots ii\end{cases}$

substitute the value of x to the first equation:

$\displaystyle \begin{cases} \displaystyle 2.2y-y= 3 \\ x = 2y \end{cases}$

simplify:

$\displaystyle \begin{cases} \displaystyle 3y= 3 \\ x = 2y \end{cases}$

divide both sides by 3:

$\displaystyle \begin{cases} \displaystyle y= 1 \\ x = 2y \end{cases}$

substitute the value of y to the second equation which yields:

$\displaystyle \begin{cases} \displaystyle y= 1 \\ x = 2 \end{cases}$

<h3>Question-3:</h3>

by order pair we obtain;

$\displaystyle \begin{cases} \displaystyle 2p + q = 2 \dots \dots i\\3q + 2p = 3 \dots \dots ii\end{cases}$

rearrange:

$\displaystyle \begin{cases} \displaystyle 2p + q = 2 \\2p + 3q= 3 \end{cases}$

subtract and simplify

$\displaystyle \begin{array}{ccc} \displaystyle 2p + q = 2 \\2p + 3q= 3 \\ \hline - 2q = - 1 \\ q = \dfrac{1}{2} \end{array}$

substitute the value of q to the first equation:

$\displaystyle 2.p+ \frac{1}{2} = 2$

make q the subject of the equation:

$\displaystyle p = \frac{3}{4}$

hence,

$\displaystyle q = \frac{1}{2} \\ p = \frac{3}{4}$

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3 years ago

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kvasek [131]

Answer:

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Step-by-step explanation: I dont care

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