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1 year ago

10

The options for the first one is left or right for the second one the options are mean or median and last ones are IQR or range

or the IQR:

1 answer:

DedPeter [7]1 year ago

6 0

With dot plot if it’s symmetrical its the mean and MAD, so i think that.

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Which number has a 3 with a value of the 3 in 3.01

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Which statements are true for the function y = |x| - 2? Select all that apply.

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3x + 1 < −2x + 8

Fantom [35]

Hello there!

The correct answer is B. Why? Well, we cannot choose A, because we don't have a multiplication sign. We cannot choose C because we also don't have a multiplication sign. However, since we have a PLUS sign and a Subtraction sign, we can say that the correct answer is option B.

3x + 1 < -2x + 8

We wanna start by subtracting 1 on both sides

3x + 1 - 1 < -2x + 8 - 1

3x < -2x + 7

Add 2x on both sides

3x + 2x < -2x + 7 + 2x

5x < 7

x < 7/5

I hope this answer helps! As always, it is my pleasure to help students like you. If you have any additional questions, feel free to comment them down below. I'll see you around!

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2 years ago

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Você é um comandante de uma espaçonave. Sua missão é chegar até Alfa Centauro em cinco anos. A distância do Sol até Alfa Centaur

Deffense [45]

Answer:

The spaceship will get to Alpha Centaur in time

Step-by-step explanation:

<u><em>The complete question in English is</em></u>

You're the commander of a spaceship. Your mission is to reach Alpha Centaur in five years. The distance from the sun to Alpha Centaur is 2.5 x 10^13 miles. The distance from Earth to Sun is approximately 9.3 x 10^7

miles. Your spaceship can travel at the speed of light. You know that light can travel a distance of 5.88 x 10^12 miles in a year. Can you get to Alpha Centaur in time?

step 1

Find the time it takes for the spaceship to travel from Earth to the Sun

The distance from the Earth to Sun is equal to

$9.3*10^7\ miles$

The spaceship can travel at the speed of light

The light can travel a distance of $5.88*10^{12}\ miles$ in a year

so

using a proportion

$\frac{5.88*10^{12}\ miles}{1\ year}=\frac{9.3*10^7\ miles}{x}\\\\x=(9.3*10^7)/5.88*10^{12}\\\\x=1.58*10^{-5} \ years$

This time is very small in years

Convert to minutes

$1.58*10^{-5} \ years=1.58*10^{-5} (365)(24)(60)=8.3\ min$

step 2

Find the time it takes for the spaceship to travel from the Sun to Alpha Centaur

The distance from the the Sun to Alpha Centaur is equal to

$2.5*10^{13}\ miles$

The spaceship can travel at the speed of light

The light can travel a distance of $5.88*10^{12}\ miles$ in a year

so

using a proportion

$\frac{5.88*10^{12}\ miles}{1\ year}=\frac{2.5*10^{13}\ miles}{x}\\\\x=(2.5*10^{13})/5.88*10^{12}\\\\x=4.25\ years$

$4.25\ years< 5\ years$

therefore

The spaceship will get to Alpha Centaur in time

3 0

2 years ago