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Molodets [167]
3 years ago
12

A bar graph can be displayed in many ways. Which of the following does NOT represent a bar graph?

Mathematics
2 answers:
DaniilM [7]3 years ago
7 0
B.scatterplot graph.
jeka943 years ago
4 0
B. Scatter plot graph
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Plss help me ASAP pls ASAP thank you
Oksana_A [137]
I think 7 is B and 8 is A, but im not really sure about this so im sorry if this is wrong
8 0
2 years ago
If 25% more than a number is 325, what is 20% less than the number?
Ahat [919]

Answer:

208

Step-by-step explanation:

8 0
3 years ago
HURRY!!!! Which equation is quadratic in form?
Natasha_Volkova [10]

Answer:

A

Step-by-step explanation:

to the power of 2

5 0
2 years ago
If you help me I will make you branliest
Rasek [7]

This exercise is about creating two-dimensional shapes. The resulting shape is a quadrilateral - Square. See the attached for the lines drawn.

What was noticed about the two lines drawn?

  • The two lines are drawn each had parallel pairs; and
  • They were perpendicular to one another.

<h3>What is the meaning of perpendicularity?</h3>

When two lines intersect with one another such that they create a right angle, perpendicularity has occurred and both lines are said to be perpendicular to one another.

Hence:

  • AB ⊥ BC
  • BC ⊥ CD
  • CD ⊥ DA; and
  • DA ⊥ AB.

Learn more about perpendicularity at:
brainly.com/question/1202004
#SPJ1

8 0
2 years ago
Very important
Veronika [31]

Using the z-distribution, we have that:

  • For a 99% confidence level, a sample size of 127 is needed.
  • For a 95% confidence level, a sample size of 74 is needed, meaning that a decrease in the confidence level decreases the needed sample size, as M and n are inverse proportional.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

For a 99% confidence interval, \alpha = 0.99, hence z is the value of Z that has a p-value of \frac{1+0.99}{2} = 0.995, so the critical value is z = 2.575.

The margin of error and population standard deviation are:

M = 3, \sigma = 13.1

Hence we have to solve for n to find the needed sample size, as follows:

M = z\frac{\sigma}{\sqrt{n}}

3 = 2.575\frac{13.1}{\sqrt{n}}

3\sqrt{n} = 2.575 \times 13.1

\sqrt{n} = \frac{2.575 \times 13.1}{3}

(\sqrt{n})^2 = \left(\frac{2.575 \times 13.1}{3}\right)^2

n = 126.4.

Rounding up, for a 99% confidence level, a sample size of 127 is needed.

For the 95% confidence interval, we have that z = 1.96, hence:

M = z\frac{\sigma}{\sqrt{n}}

3 = 1.96\frac{13.1}{\sqrt{n}}

3\sqrt{n} = 1.96 \times 13.1

\sqrt{n} = \frac{1.96 \times 13.1}{3}

(\sqrt{n})^2 = \left(\frac{1.96 \times 13.1}{3}\right)^2

n = 73.3.

Rounding up, for a 95% confidence level, a sample size of 74 is needed, meaning that a decrease in the confidence level decreases the needed sample size, as M and n are inverse proportional.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

6 0
1 year ago
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