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aalyn [17]
3 years ago
14

I need help with this problem.

Mathematics
1 answer:
puteri [66]3 years ago
8 0
Your answer would be 30 

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Classify the scenarios based on whether they are observational studies, experiments, or surveys. Scenario A: Twenty employees of
viktelen [127]

Answer:

Just took test, got it right. In the following:

Step-by-step explanation:

Scenarios:

A- Survey

B- Observation

C- Experiment

D- Survey

6 0
3 years ago
Simplify the following expression.
o-na [289]

Answer:

i dont know what you mean but

3x(4x-3) simplified is 12x - 4 or 12x+(-4)

3 0
3 years ago
The mean amount spent by a family of four on food per month is $500 with a standard deviation of $75. Assuming that the food cos
JulijaS [17]

Answer:

The probability that a family spends less than $410 per month

P( X < 410) = 0.1151

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given mean of the population = 500 </em>

<em>Given standard deviation of the Population = 75</em>

Let 'X' be the variable in normal distribution

      Z = \frac{x-mean}{S.D}

<em>Given X = $410</em>

<em></em>Z = \frac{410-500}{75} = - 1.2<em></em>

<u><em>Step(ii):-</em></u>

The probability that a family spends less than $410 per month

P( X < 410) = P( Z < - 1.2 )

                  =  0.5 - A( -1.2)

                 = 0.5 - A(1.2)

                = 0.5 - 0.3849  ( ∵from normal table)

                = 0.1151

<u>Final answer:-</u>

The probability that a family spends less than $410 per month

P( X < 410) = 0.1151

6 0
3 years ago
Can someone plz help this is like my 5th time putting up this question!!!
serg [7]

Answer:

the table should be 25,98,173,248

3 0
3 years ago
suppose your grandparents started a savings acct for your on first birthday with a deposit of 100. On your second birthday they
Likurg_2 [28]
1st birthday-100
2nd birthday-200
3rd birthday- 300
4th birthday- 400
5th birthday- 500
6th birthday- 600
7th birthday- 700
8th birthday- 800
9th birthday- 900
10th birthday- 1,000
4 0
3 years ago
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