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laiz [17]
3 years ago
10

The Answer to thevbenvn

Mathematics
1 answer:
Pepsi [2]3 years ago
4 0

Answer:

what are you asking it is only a picture of 2/4

You might be interested in
¿What is the density of a rock if it has a mass of 50 g and a volume of 10 mL?
yan [13]

D=m/v so d=50/10=5

The density is 5g/ml

It might be ml^3 (5g/ml^3) but I don’t remember

4 0
3 years ago
Linda received 4/5 of the votes in the votes in the election for student council president.what percent of votes did Linda recei
Mariana [72]

Answer:

80% 0.8

Step-by-step explanation:

To find the percentage out of a fraction you would divide 4÷5 to get 0.8, the decimal answer, then to turn that to a percent you would move the point two places to the right to get 80%.

6 0
3 years ago
33. Suppose you were on a planet where the
tatyana61 [14]

<u>Answer:</u>

a) 3.675 m  

b) 3.67m

<u>Explanation:</u>

We are given acceleration due to gravity on earth =9.8ms^-2

And on planet given = 2.0ms^-2

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula  </u>

\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}

Where H = max jump height,  

v0 = velocity of jump,  

Ø = angle of jump and  

g = acceleration due to gravity

Considering velocity and angle in both cases  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)  

g1 = 2.0ms^-2 and  

g2 = 9.8ms^-2

Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by  </u>

 \mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}

which is due to projectile motion of ball  

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,  

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0ms^-2  and g2 = 9.8ms^-2

We get h1 = 3.67m which is the required height

6 0
3 years ago
What is the lcm 3 and 10
alukav5142 [94]

30, you could just multiply both numbers, but it's also better to list out the factor until both match

6 0
3 years ago
Read 2 more answers
Simplify 13x + 7y - 2x + 6a
VLD [36.1K]

Step-by-step explanation:

13x+7y-2x+6a

combine like terms

=13x-2x+7y+6a

=11x+7y+6a

simplified

8 0
3 years ago
Read 2 more answers
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