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Lubov Fominskaja [6]
2 years ago
14

License plates in a particular state display 3 letters followed by 3 numbers. How many different license plates can be manufactu

red? (Repetitions are allowed.)
Mathematics
1 answer:
netineya [11]2 years ago
5 0

Using the fundamental counting theorem, it is found that 17,576,000 different license plates can be manufactured.

Fundamental counting theorem:

States that if there are n things, each with n_1, n_2, \cdots, n_n ways to be done, each thing independent of the other, the number of ways they can be done is:

N = n_1 \times n_2 \times \cdots \times n_n

In this problem:

  • Since repetition is allowed, for the 3 letters, there are 26 outcomes, hence n_1 = n_2 = n_3 = 26.
  • For the 3 numbers, there are 10 outcomes, hence n_4 = n_5 = n_6 = 10

Then:

N = 26^3 \times 10^3 = 17576000

17,576,000 different license plates can be manufactured.

To learn more about the fundamental counting theorem, you can take a look at brainly.com/question/24314866

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Answer:

f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.

Step-by-step explanation:

Given

9 < x < 10 --- interval

Required

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f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

Solve

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f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.

The CDF is:

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F(v) = \frac{1}{3}v^{-\frac{2}{3}}

So:

f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.

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