3 years ago

16.

Mathematics

2 answers:

Pachacha [2.7K]3 years ago

4 0

Answer:

Step-by-step explanation:

Dmitry_Shevchenko [17]3 years ago

3 0

Answer:

Step-by-step explanation:

THEY AVOID STUFF THAT HURTS THEIR BUISSNESS AND THEY HAVE TO TAKE RISKS THAT CAN LEAVE THEM BROKE

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What is the area of the square if one side is 4cm? How do you know?

Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

Area of square=L^2

A=4cm ×4cm

A=16cm^2

5 0

3 years ago

Read 2 more answers

Precalc.

viktelen [127]

Domain: x>0.

$(\log_2x)^2+7\log_2x+12=0$

Substitute $t=\log_2x\in\mathbb{R}$ . We have:

$t^2+7t+12=0\\\\a=1\qquad b=7\qquad c=12\\\\\\\Delta=b^2-4ac=7^2-4\cdot1\cdot12=49-48=1\\\\\sqrt{\Delta}=\sqrt{1}=1\\\\\\
t_1=\dfrac{-b-\sqrt{\Delta}}{2a}=\dfrac{-7-1}{2}=\dfrac{-8}{2}=-4\\\\\\
t_2=\dfrac{-b+\sqrt{\Delta}}{2a}=\dfrac{-7+1}{2}=\dfrac{-6}{2}=-3$

For t₁ there will be:

$\log_2x=t_1\\\\\log_2x=-4\\\\2^{-4}=x\\\\x=\dfrac{1}{2^4}\\\\\\x=\dfrac{1}{16}=0,0625\\\\\\\boxed{x\approx0,063}$

and for t₂:

$\log_2x=t_2\\\\\log_2x=-3\\\\2^{-3}=x\\\\x=\dfrac{1}{2^3}\\\\\\x=\dfrac{1}{8}\\\\\\\boxed{x=0,125}$

Answer d)

6 0

3 years ago

Solve (x + 1)2 – 4(x + 1) + 2 = 0 using substitution. u = Select the solution(s) of the original equation.

Semenov [28]

(x - 1)2 - 4(X + 1) + 2 = 0

2x - 2 - 4x - 4 + 2 = 0

(2x - 4x) - 4 = 0

-2x = 4

x = 4/-2

x = -2

8 0

3 years ago