X^2+12x=0
(ax^2+bx)=0
(b/2)^2=(12/2)^2=(6)^2=36
x^2+12x+36=(x+6)^2
20 is the slope and 30 is the y-intercept
Answer:
Vertical Asymptotes: x=-2,2
Horizontal Asymptotes: y=1
Step-by-step explanation:
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Answer:
256 m and 3840 m²
Step-by-step explanation:
The 3 part of the ratio represents 48 m , then
48m ÷ 3 = 16 m ← value of 1 part of the ratio, so
5 parts = 5 × 16 m = 80 m
Then breadth = 48 m and length = 80 m
perimeter = 2l + 2b = 2(80) + 2(48) = 160 + 96 = 256 m
area = lb = 80 × 48 = 3840 m²
Answer:
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Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)
I really need this question answered
By:
I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).
I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.
The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:
y = 6x + b
We need to find b, so substitute the point (-5,4) that we know is on the line:
4 = 6*(-5) + b and solve for b
4 = -30 + b
b = 34
The line is y = 6x + 34
