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andrew11 [14]
3 years ago
7

What is the approximate area of the circle shown below?

Mathematics
1 answer:
Stels [109]3 years ago
3 0

Answer:

3848 in^{2}

Step-by-step explanation:

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Please help me this is. big
kramer

Answer:

C. = 69.5

Step-by-step explanation:

The median or the average between 80 and 59 is 69.5

Hope this helps! :)

8 0
3 years ago
Find two integers a and b between 1 and 20 such a a^2+b^2 is a perfect square
guajiro [1.7K]
4,9,16 are all options that ratio to 1,2,3
8 0
3 years ago
Helppp me pleaseeeeee !!!
ad-work [718]

Answer:

300 liters

The slope of the line is 300

Step-by-step explanation:

5 0
3 years ago
Need help with questions 23 & 25
BaLLatris [955]

23. You are expected to be familiar with the relationship

... cost + markup = selling price

a) cost + $23.99 = $119.95

... cost = $119.95 -23.99 = $95.96

b) The markup as a fraction of cost is

... markup/cost = $23.99/$95.96 = 0.25 = 25%

c) cost + markup = selling price . . . . the equation we started with

... cost/cost + markup/cost = (selling price)/cost . . . . divide by cost

... 100% + 25% = (selling price)/cost = 125%

25.

a) See part c) of problem 23. Selling price is 126% of cost.

b) Selling price = $450 × 1.26 = $567

c) Markup = $450 × 0.26 = $117

6 0
3 years ago
Solve each of the following systems of equations by substitution
Delvig [45]

Answer:

1) The solution to the given equations is (3,6)

2) The solution to the given equations is (7,-1)

3) The solution to the given equations is (6,5)

Step-by-step explanation:

1) Given equations are x+y=5\hfill (1)

and x=1+y\hfill (2)

To solve the given equations by substitution method :

From equation (2) we have the value x=1+y

Substitute the value of x=1+y  in equation (1) we get

(1+y)+y=5

1+y+y=5

1+2y=5

2y=5-1

2y=4

y=\frac{4}{2}

Therefore y=2

Now substitute the value of y=2 in equation (2) we get

x=1+y

x=1+2

Therefore x=3

The solution is (3,6)

2) Given equations are 2x+3y=11\hfill (1)

and x+y=6\hfill (2)

To solve the given equations by substitution method :

From equation (2) we have the value x=6-y

Substitute the value of x=6-y  in equation (1) we get

2(6-y)+3y=11

12-2y+3y=11

y=11-12

Therefore y=-1

Now substitute the value of y=-1 in equation (2) we get

x+(-1)=6

x=6+1

Therefore x=7

The solution is (7,-1)

3) Given equations are x-y=1\hfill (1)

and 6x-7y=1\hfill (2)

To solve the given equations by substitution method :

From equation (1) we have the value x=1+y

Substitute the value of x=1+y  in equation (2) we get

6(1+y)-7y=1

6+6y-7y=1

-y=1-6

Therefore y=5

Now substitute the value of y=5 in equation (1) we get

x-5=1

x=1+5

Therefore x=6

The solution is (6,5)

8 0
3 years ago
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