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earnstyle [38]
3 years ago
8

Which of the sets of ordered pairs represents a function?

Mathematics
1 answer:
Marrrta [24]3 years ago
7 0

Answer:

Set A

Step-by-step explanation:

By definition "a function may NOT have two y-values assigned to the same x-value, [but] it may have two x-values assigned to the same y-value."(https://mathbitsnotebook.com/Algebra1/Functions/FNFuncBasics.html)

Set A has follows this set of rules while Set B does not. Also if we graph it, Set B does not pass the vertical line test. (Learn about the vertical line test in the link below).

http://www.coolmath.com/algebra/15-functions/03-vertical-line-test-01

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In an orchestra, there are 15 woodwind players to 24 brass players. What is the ratio of woodwind players to brass players, writ
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Answer:

15/24 =5/8 th ratio 5/8

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What is 3550/5 as a regular fraction
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it can not be made into a regular fraction. but it can be made into a whole number. the whole number would be 710

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The world's population is expected to grow at a rate of 1.3% per year until at least the year 2020. In 1994 the total population
Marina CMI [18]
The solution to your problem is as follows:

Given: 
P₀ = 5,642×10^6 people, 
i = 1.3% = 0.013 per year, 
n = 2020 - 1994 = 26 years, 

We get: 
<span>
Pn = P₀ e^(i.n) </span>
. . .= 5,642×10^6×e^(0.013×26) 
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Therefore, the </span>the world's predicted population in the year 2020 is <span>7,911×10^6 people.


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5 0
3 years ago
The speeds of vehicles traveling on a highway are normally distributed with a population standard deviation of 7 miles per hour
True [87]

Answer:  (56.03\ ,63.97)

Step-by-step explanation:

Given : The speeds of vehicles traveling on a highway are normally distributed .

Standard deviation: \sigma: 7

Since , sample size : n=20 , which is small sample (n<30) so the test applied here is a t-test.

Degree of freedom= n-1=20-1=19

Sample mean : \overline{x}=60

Level of significance : 1-\alpha:0.98

Then , significance level : \alpha: 1-0.98=0.02

Using t-distribution table , Critical value : \text{t-score}=t_{n-1, \alpha/2}= 2.539483

The confidence interval for population mean is given by :-

\overline{x}\pm t_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

60\pm( 2.539483)\dfrac{7}{\sqrt{20}}\approx60\pm3.97=(56.03\ ,63.97)

Hence, a 98% confidence interval for the population mean=(56.03\ ,63.97)

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3 years ago
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