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3 years ago

Which of the sets of ordered pairs represents a function?

Mathematics

1 answer:

Marrrta [24]3 years ago

7 0

Answer:

Set A

Step-by-step explanation:

By definition "a function may NOT have two y-values assigned to the same x-value, [but] it may have two x-values assigned to the same y-value."(https://mathbitsnotebook.com/Algebra1/Functions/FNFuncBasics.html)

Set A has follows this set of rules while Set B does not. Also if we graph it, Set B does not pass the vertical line test. (Learn about the vertical line test in the link below).

http://www.coolmath.com/algebra/15-functions/03-vertical-line-test-01

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What is 304.00 in expanded and word form

jenyasd209 [6]

Answer:

304 = 300 + 00 + 4, expanded form

Word form three hundred four and (double zero)

pls don’t eliminate this question nor give brainliest.

8 0

2 years ago

Read 2 more answers

Find the length of the hypotenuse

kati45 [8]

Answer: 12

Step-by-step explanation:

a^2 times b^2 =c^2

4^2 times 3^2=c^2

16 times 9=c^2

144=c^2

$\sqrt{144}$ = $\sqrt{c^2}$

12=c

7 0

3 years ago

How does the unit circle allow the trigonometric functions to be defined for all real numbers instead of just for acute angles?

Molodets [167]

Every point in the unit circle is identified either by its coordinates $(x,y)$ or by the angle it forms with the x-axis, $\alpha$ .

The trigonometric functions associate with every angle $\alpha$ and the correspondant $(x,y)$ coordinates the two values

$\cos(\alpha)=x,\quad\sin(\alpha)=y$

This procedure can be done for every angle $\alpha$ , so you don't have to work with acute angles only.

8 0

2 years ago

PLS HELP ILL GIVE BRAINLIEST

inysia [295]

<h3>Answer: 14x - 8</h3>

=======================================================

Explanation:

I'll use the quadratic formula to find the roots or x intercepts. This slight detour allows us to factor without having to use guess-and-check methods.

The equation is of the form ax^2+bx+c = 0

a = 12
b = -11
c = -5

This leads to...

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-11)\pm\sqrt{(-11)^2-4(12)(-5)}}{2(12)}\\\\x = \frac{11\pm\sqrt{361}}{24}\\\\x = \frac{11\pm19}{24}\\\\x = \frac{11+19}{24} \ \text{ or } \ x = \frac{11-19}{24}\\\\x = \frac{30}{24} \ \text{ or } \ x = \frac{-8}{24}\\\\x = \frac{5}{4} \ \text{ or } \ x = -\frac{1}{3}$

Now use those roots to form these steps

$x = \frac{5}{4} \ \text{ or } \ x = -\frac{1}{3}\\\\4x = 5 \ \text{ or } \ 3x = -1\\\\4x - 5 =0 \ \text{ or } \ 3x+1 = 0\\\\(4x-5)(3x+1) = 0$

Refer to the zero product property for more info.

Therefore, the original expression factors fully to (4x-5)(3x+1)

Use the FOIL rule to expand it out and you should get 12x^2-11x-5 again.

----------------------------------------------

We did that factoring so we could find the side lengths of the rectangle.

I'm using the fact that area = length*width

L = length = 4x-5
W = width = 3x+1

The order of length and width doesn't matter.

From here, we can then compute the perimeter of the rectangle

P = 2(L+W)

P = 2(4x-5+3x+1)

P = 2(7x-4)

P = 14x - 8

6 0

2 years ago

Solve the equation on the<br> interval [0, 27r).<br> 4(sin x)2 - 2 = 0

Ket [755]

$4[sin(x)]^2 - 2 = 0\implies 4[sin(x)]^2=2\implies [sin(x)]^2=\cfrac{2}{4}\implies [sin(x)]^2=\cfrac{1}{2} \\\\\\ sin(x)=\pm\sqrt{\cfrac{1}{2}}\implies sin^{-1}[sin(x)]=sin^{-1}\left( \pm\sqrt{\cfrac{1}{2}} \right)\implies x=sin^{-1}\left( \pm\sqrt{\cfrac{1}{2}} \right)$

$x=sin^{-1}\left( \pm\cfrac{\sqrt{1}}{\sqrt{2}} \right)\implies x=sin^{-1}\left( \pm\cfrac{1}{\sqrt{2}} \right)\implies x=sin^{-1}\left( \pm\cfrac{\sqrt{2}}{2} \right) \\\\[-0.35em] ~\dotfill\\\\ ~\hfill x=\cfrac{\pi }{4}~~,~~\cfrac{3\pi }{4}~~,~~\cfrac{5\pi }{4}~~,~~\cfrac{7\pi }{4}~\hfill$

Check the picture below.

4 0

2 years ago