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shtirl [24]
3 years ago
14

A company wishes to test LaTeX: H_0 H 0 : LaTeX: p=0.75 p = 0.75 against LaTeX: H_a H a : LaTeX: p\ne0.75 p ? 0.75 , where LaTeX

: p p refers to the unknown proportion of skilled workers in the company. Given the sample data, the p-value for this test is found to be 0.0251. What conclusion can be made about the test? (a) Accept the null hypothesis at 3% level of significance. (b) Reject the null hypothesis at 3% level of significance.
Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
8 0

Answer:

B

Step-by-step explanation:

The p-value 0.0251 is less than the significance level 0.03, so the null hypothesis is rejected

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Pls help idk how to do this<br><br>''solve for the angle with Trig''<br><br>Solve for 0<br>​
nalin [4]

Answer:

24.15

Step-by-step explanation:

4 0
3 years ago
meteroloogist track severe stoms using Doppler radar. A polar grid is used to measure distances as the storms progress. If the c
FinnZ [79.3K]

Answer:

$(x-h)^2+(y-k)^2= (r+ 40 )^2$  

Step-by-step explanation:

It is given that a meteorologist is using a Doppler radar to find out the distance of the storm as it passes using a polar grid.

The origin of the radar screen is its center.

And the distance between each ring is 10 miles from the center.

So let :

r = radius

h and k = be the coordinates of the center.

So the equation of a circle is :

$(x-h)^2+(y-k)^2= r^2 $

Now the equation of the fourth circle when the radius changes by 10 miles is :

$(x-h)^2+(y-k)^2= (r+ 40 )^2$  

5 0
3 years ago
Noya needs to determine the number of books that will fit into a box. If the box has a length of 18 inches and each book is Star
natima [27]

Answer:

A. 18÷2/9

Step-by-step explanation:

A. 18÷2/9

B. 18×2/9

C. 2/9÷18

D. 9/2÷18

Let

Total length of box = 18 inches

Thickness of each book = 2/9 inches

Number of books that will fit into the box = x

Number of books that will fit into the box = Total length of box ÷ Thickness of each book

x = 18 ÷ 2/9

= 18 × 9/2

= 162/2

= 81 books

The correct answer is A. 18÷2/9

7 0
3 years ago
. Use the quadratic formula to solve each quadratic real equation. Round
Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}, with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}

\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5

So B has two solutions of 5 and -1.5.

Now to C!

\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}

\frac{44}{8} = 5.5

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0
3 years ago
Help me please: answer as an improper fraction
rewona [7]
1) \frac{7}{24}
2) \frac{2}{7} 
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4) \frac{3}{14}
5) \frac{1}{3}
6) \frac{7}{20}
7) \frac{6}{10}
8) \frac{1}{12}
9) \frac{1}{3}
10) \frac{1}{90}
11) \frac{1}{40}
12) \frac{1}{50}
13) \frac{20}{21}
14) \frac{1}{4}
15) \frac{5}{6}
16) \frac{9}{35}
17) \frac{35}{12} ( 2 \frac{11}{12} )
18) \frac{9}{1} (9)
7 0
3 years ago
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