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lorasvet [3.4K]
1 year ago
9

suppose the mean height for men is 70 inches with a standard deviation of 2 inches. What percentage of men are less than 74 inch

es tall?
Mathematics
1 answer:
Ratling [72]1 year ago
3 0

Answer:

97.7 %

Step-by-step explanation:

TWO standard deviations above the mean

  z - score = 2   corresponds to .9772    97.7 %

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On Novenber 4, your bank statement shows a balance of $2,253.18. Your checkbook shows a balance of $2,324.34. If there are outst
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Answer:

The final answer is "$2387.85 and $2594.85".

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Given values:

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The checkbook balance = $2,324.34

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service charge= $5.00

Adjusted Checkbook Balance =?

Adjusted  Statement Balance=?

Adjusted the Checkbook Balance:

checkbook balance = $2,324.34

\text{total checkbook balance = checkbook balance+ credits}\\

                                      = \$ 2,324.34+ \$ 68.51\\\\= \$ 2392.85

\text{ Adjust check book balance= total checkbook balance - servicec  charge}

                                         = \$2392.85 - \$5.00\\\\= \$ 2387.85

Adjusted the Statement Balance:

bank statement balance= $2,253.18

\text{total Statement balance = bank  Statement balance+  transit amount}\\

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\text{outstanding check amounts = $105.50+ $158.10}

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8 0
3 years ago
There are 24 basketball teams competing in a tournament. After each round half the teams are eliminated. This situation can be m
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3 years ago
Find a cubic function with the given zeros.
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Answer:

The correct option is D) f(x) = x^3 + 2x^2 - 2x - 4 .

Step-by-step explanation:

Consider the provided cubic function.

We need to find the equation having zeros: Square root of two, negative Square root of two, and -2.

A "zero" of a given function is an input value that produces an output of 0.

Substitute the value of zeros in the provided options to check.

Substitute x=-2 in f(x) = x^3 + 2x^2 - 2x + 4 .

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Therefore, the option is incorrect.

Substitute x=-2 in f(x) = x^3 + 2x^2 + 2x - 4 .

f(x) = x^3 + 2x^2 + 2x - 4\\f(x) = (-2)^3 + 2(-2)^2 + 2(-2) - 4\\f(x) =-8+2(4)-4-4\\f(x) =-8

Therefore, the option is incorrect.

Substitute x=-2 in f(x) = x^3 - 2x^2 - 2x - 4 .

f(x) = x^3 - 2x^2 - 2x - 4\\f(x) = (-2)^3 - 2(-2)^2 - 2(-2) - 4\\f(x) =-8-8+4-4\\f(x) =-16

Therefore, the option is incorrect.

Substitute x=-2 in f(x) = x^3 + 2x^2 - 2x - 4 .

f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-2)^3+2(-2)^2 - 2(-2) - 4\\f(x) =-8+8+4-4\\f(x) =0

Now check for other roots as well.

Substitute x=√2 in f(x) = x^3 + 2x^2 - 2x - 4 .

f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (\sqrt{2})^3+2(\sqrt{2})^2 - 2(\sqrt{2}) - 4\\f(x) =2\sqrt{2}+4-2\sqrt{2}-4\\f(x) =0

Substitute x=-√2 in f(x) = x^3 + 2x^2 - 2x - 4 .

f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-\sqrt{2})^3+2(-\sqrt{2})^2 - 2(-\sqrt{2}) - 4\\f(x) =-2\sqrt{2}+4+2\sqrt{2}-4\\f(x) =0

Therefore, the option is correct.

8 0
3 years ago
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