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lorasvet [3.4K]

2 years ago

9

suppose the mean height for men is 70 inches with a standard deviation of 2 inches. What percentage of men are less than 74 inch

es tall?

1 answer:

Ratling [72]2 years ago

3 0

Answer:

97.7 %

Step-by-step explanation:

TWO standard deviations above the mean

z - score = 2 corresponds to .9772 97.7 %

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PLEASE HELP! TIME RUNNING OUT ,EXPLAIN THIS TO ME!!Dilation D Dv,2/5 was performed on a rectangle. How does the image relate to

Delvig [45]

Answer:

Options A ,B and E

Step-by-step explanation:

Here 2/5 is less then one then all sides are gonna 2/5 of initial length hence reduction occur.

Angles are not gonna affected because it is like zoom in.

Center of dilation can be anywhere as point Q is not specified in question thus it is wrong.

Yeah base of rectangle is reduced by a factor of 2/5.

5 0

3 years ago

Race relations: A New York Times/CBS poll surveyed 1,027 adults nationwide about race relations in the United States. Of the sam

Montano1993 [528]

Answer:

D. We are 95% confident that the proportion of all Americans who say that race relations in this country are generally bad is between 58% and 64%.

Step-by-step explanation:

The 95% confidence interval refers that 95% of data is correct with respect of the population

Given that 95% confidence interval is (0.58, 0.64)

So based on this, the option D is correct as it shows the right thing with regard to 95% confidence interval

Therefore all the other options are incorrect as the first option is of probability, the second option is the sample, and the third option is of statement form i.e not standardized.

7 0

4 years ago

After driving for 2.2 hours (2 hours and 12 mintues), marcos' total distance traveled was 153 miles. at what constant speed (in

vova2212 [387]

<span>Time = Distance/Speed
Time = 153/70

Time = 2.19 hours.
Time = 2 hours 11 minutes.
Hope this helps.
:-)</span>

8 0

4 years ago

Read 2 more answers

Do logarithmic functions have horizontal asymptotes?

Marta_Voda [28]

9514 1404 393

Answer:

not generally

Step-by-step explanation:

The basic log function has a vertical asymptote where its argument is zero. It has a positive slope for all positive arguments. It tends to infinity as the argument tends to infinity. There is no horizontal asymptote.

__

A log function can be made part of a larger expression in a way that would give the expression a horizontal asymptote. For example, the function ...

f(x) = 1/log(x)

has a horizontal asymptote at f(x) = 0. (This asymptote is approached very slowly.)

8 0

3 years ago

Historical data indicates that only 20% of cable customers are willing to switch companies. If a binomial process is assumed, th

Natasha_Volkova [10]

Answer:

a. The probability is 0.735

b. The probability is 0.6296

c. The probability is 0

Step-by-step explanation:

If we assume a binomial process, the probability that x customer are willing to switch companies is:

$P(x)=nCx*p^{x}*(1-p)^{n-x}$

nCx is calculated as:

$nCx=\frac{n!}{x!(n-x)!}$

Where n are the 20 cable customers and p is the probability 0.2 that the cable customer are willing to switch companies.

Then, P(x) is:

$P(x)=20Cx*0.2^{x}*(1-0.2)^{20-x}$

The probability that between 2 and 5 (inclusive) customers are willing to switch companies is:

P(2≤x≤5) = P(2) + P(3) + P(4) + P(5)

Where P(2), P(3), P(4) and P(5) are equal to:

$P(2)=20C2*0.2^{2}*(1-0.2)^{20-2}=0.1369$

$P(3)=20C3*0.2^{3}*(1-0.2)^{20-3}=0.2054$

$P(4)=20C4*0.2^{4}*(1-0.2)^{20-4}=0.2182$

$P(5)=20C5*0.2^{5}*(1-0.2)^{20-5}=0.1745$

So, P(2≤x≤5) is:

P(2≤x≤5) = 0.1369 + 0.2054 + 0.2182 + 0.1745 = 0.735

At the same way, the probability that less than 5 customers are willing to switch is:

P(x<5)=P(0)+P(1)+P(2)+P(3)+P(4)

P(x<5)=0.6296

Finally, the probability that more than 16 customers are willing to switch is:

P(x>16)=P(17)+P(18)+P(19)+P(20)

P(x>16)=0

7 0

4 years ago