We are asked to solve for the surface area of the described figure in the problem. We can conclude that the given figure is a rectangular prism since it was being mentioned in the problem that the height is laid flat. Therefore, the formula for the surface area is SA = PH + 2B where "P" stands for the perimeter of the rectangle and "B" stands for the area of the rectangle while "H" is for the height.
Solving for P, we have it:
P = width + length + width + length
P = 10 + 5 + 10 + 5
P = 30 inches
Solving for B, we have it:
B = length * width
B = 10 * 5
B = 50 inches squared
Solving for the surface area, we have it:
SA = PH + 2B
SA = 30*7 + (2*50)
SA = 310 inches squared
The answer is 310 in2.
Answer:
a) 0.018
b) 0
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 14.4 in
Standard Deviation, σ = 1 in
We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.
Formula:

a) P(breadth will be greater than 16.5 in)
P(x > 16.5)


Calculation the value from standard normal z table, we have,

0.018 is the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.5 in.
b) P( with 123 randomly selected men, these men have a mean hip breadth greater than 16.5 in)
Formula:
P(x > 16.5)

Calculation the value from standard normal z table, we have,

There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in
Answer: true
Step-by-step explanation: they are all equivalent
Answer:
X = .5
Step-by-step explanation:
10 × 20 = 200
10.5 × 20 = 210
Explanation:
Y = 210
210 = 20(10+X)
divide both sides by 20
10.5 = 10+X
subtract 10 from both sides
.5 = X
X = .5