The area of the quarter circle with radius 3ft is 
Area of a quarter circle is given by the formula:
Where r represents the radius of the circle
In the quarter circle shown, the radius, r = 3 feet
π = 3.14
Substitute π = 3.14 and r = 3 into the formula
The area of the quarter circle with radius 3ft is
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Answer:
Step-by-step explanation:
You must share g(x).
Working with what you've already shared:
h(x) = f(x) + g(x)
= x + 6 + g(x)
<h3>The solution is (x, y) = (3, -24)</h3>
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
-3x - y = 15 -------- eqn 1
y = -8x ------ eqn 2
We have to find solution of (x, y)
We can solve by substitution method
<em><u>Substitute eqn 2 in eqn 1</u></em>
-3x - (-8x) = 15
-3x + 8x = 15
5x = 15
Divide both sides by 5
<h3>x = 3</h3>
Substitute x = 3 in eqn 2
y = -8(3)
<h3>y = -24</h3>
Thus solution is (x, y) = (3, -24)
Answer:
<em><u>x=-6, y=-2</u></em>, (As a point) (-6, -2).....The point form is not necessary unless you want to solve the system (of equations) by graphing.
Step-by-step explanation:
By substitution:
x-y=-4 By adding y on both sides,
x=y-4
Now you can substitute x for the expression (y-4)
Plug the (y-4) as x in the other equation.
So -2x+3y=6 becomes
-2(y-4)+3y=6
Now solve:
-2(y-4)+3y=6 distributes out to be
-2y+8+3y=6 Now combining like terms
y+8=6 Subtract 8 on both sides to isolate the variable
<u><em>y=-2</em></u>
Now plug the value -2 in where the y is in any equation (preferably the easier/less complicated one) and solve for x.
So x-y=-4 becomes
x-(-2)=-4
=x+2=-4
=<u><em>x=-6</em></u>
