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2 years ago

Linear Function

Mathematics

2 answers:

makkiz [27]2 years ago

7 0

Answer:

Step-by-step explanation:

Where we analyse a linear function, we must consider variations of each variable.

Also, linear functions variate according to its constant ratio of change, which is defined as

$r=\frac{\Delta y}{\Delta x}$

Which is the variation of the vertical value, regarding x-values.

So, if we want to show this variation, we must include a colum $\Delta y$ , which shows the variation we need, because it's the dependent value, then we can analyse the variation of the function for a certain x-interval.

Therefore, the right answer is B.

monitta2 years ago

3 0

B because x is the independent variable; you could choose any number for x

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Plzzz explain this question in detail

Svet_ta [14]

Step-by-step explanation:

hi sis !! please ask me if u dont understand

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3 years ago

PLEASE ALSO EXPLAIN HOW TO SOLVE THIS. 20 POINTS

eimsori [14]

B.) Hibiscus Street

The key thing to remember is the slope of the lines. The equation for a line in slope intercept form is
y = ax + b
where
a = slope
b = y intercept

So the equation for Oak Street is y = 2/3x - 7. So it's slope is 2/3. And any street that has the same slope will be given a tree name. And any street that's perpendicular will be given a flower name. You can determine is a line is perpendicular if it has a slope that's the negative reciprocal. So a street that's perpendicular to Oak street will have a slope of -3/2.

Now you've just been given the equation to a new street that's y = -3/2x - 2. Since the slope is -3/2 and Oak street has a slope of 2/3, the new street is perpendicular to Oak street. And given the naming scheme, that means that the new street will have the name of a flower. So let's look at the available street names and pick a flower.
<span>
A.) Weeping Willow Street
* Nope a Weeping Willow is a tree. So this name won't work.

B.) Hibiscus Street
* Yes. A Hibiscus is a flower, so this name is suitable.

C.) Oak Street
* Nope. Not only is this a tree instead of a flower, but there's already an Oak street. So bad choice.

D.) Panther Street
* Nope, this is an animal, not a flower. Bad choice.

</span>

6 0

3 years ago

Find the median. 90, 88, 100, 82, 80.<br> PLEASE

Ludmilka [50]

Answer:

Step-by-step explanation:

80, 82, 88, 90, 100

Now cross out the numbers starting with 80 and 100 and keep going till you get the middle number which would be 88

5 0

2 years ago

Read 2 more answers

What is the possible rational roots for this polynomial 6x³+5x²+10x+3=0

8090 [49]

Answer:

See below.

Step-by-step explanation:

Using the Rational Roots Theorem:

Factors of 3: 1, 3 ( = p).

Factors of 6: 1,2,3,6 ( = q).

Possible real roots are a 1 or 3 from p / q = +/- 1/1, +/- 3/1 , +/-1/2, +/- 1/3 , +/- 1/6, +/- 3/2.

3 0

2 years ago

Please help

Zolol [24]

Given:

The function is

$r(x)=0.05(x^2+1)(x-6)$

where, function r gives the instantaneous growth rate of a fruit fly population x days after the start of an experiment.

To find:

Number of complex and real zeros.

Time intervals for which the population increased and population deceased.

Solution:

We have,

$r(x)=0.05(x^2+1)(x-6)$

$r(x)=0.05(x^3+x-6x^2-6)$

Here, degree of function x is 3. It means, the given function has 3 zeros.

From the given graph it is clear that, the graph of function r(x) intersect x-axis at once.

So, the given function r(x) has only one real root and other two real roots are complex.

Therefore, function r has 2 complex zeros and one real zero.

Before x=6, the graph of r(x) is below the x-axis and after that the graph of r(x) is above the x-axis.

Negative values of r(x) represents the decrease in population and positive value of r(x) represents the increase in population.

Therefore, based on instantaneous growth rate, the population decreased between 0 and 6 hours and the population increased after 6 hours.

3 0

2 years ago