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3 years ago

What is the measure of

Mathematics

2 answers:

pashok25 [27]3 years ago

6 0

The measure of is idk you have to tell me the measurement first :)

Ilya [14]3 years ago

5 0

Need more info but i’m happy to answer in the comments:)

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Suppose there are signs on the doors to two rooms. The sign on the first door reads "In this room there is a lady, and in the ot

9966 [12]

Answer:

The lady is on the second door

Step-by-step explanation:

we have that

The sign on the first door reads "In this room there is a lady, and in the other one there is a tiger"

The sign on the second door reads "In one of these rooms, there is a lady, and in one of them there is a tiger."

The sign on the second door is true

The sign on the first door is true or false

Since one of these signs is true and the other is false, the sign in the first door must be false

therefore

The lady is on the second door

5 0

3 years ago

What is the area of this triangle? A=bh2 17 m² 30 m² 60 m² 120 m² Right triangle with height labeled 12 m, base labeled 5 m, and

vichka [17]

Answer:

30 m²

Step-by-step explanation:

What is the area of this triangle? A=bh/2 17 m² 30 m² 60 m² 120 m² Right triangle with height labeled 12 m, base labeled 5 m, and third side labeled 13 m.

Area of a triangle = bh/2

b = Base = 5m

h = Height = 12m

Area of the triangle = 5m × 12m/2

= 60m²/2

= 30 m²

6 0

2 years ago

(50 points) Use the spinner below. Show your work, making sure to simplify your answers. (Note: The smallest section of the circ

Verizon [17]

Answer:

16. 3/8
17. 1/8
18. 5/18
19. 0
20. 1

Step-by-step explanation:

As per the spinner we have:

Green = 1/2 - 1/16 = 7/16
Red = 1/4
Purple = 1/8
Orange, blue, yellow = 1/16

16. P(red, yellow, blue) = ?

P = 1/4 + 1/16 + 1/16 = 3/8

17. P(orange, yellow) = ?

P = 1/16 + 1/16 = 1/8

18. P(green, blue, purple) = ?

P = 7/16 + 1/16 + 1/8 = 10/16 = 5/8

19. P(pink) = ?

P = 0 as no pink section

20. P(red, orange, yellow, green, blue, purple) = ?

P = 1 as all possible colors selected

6 0

2 years ago

Please solve, answer choices included.

qaws [65]

4. To solve this problem, we divide the two expressions step by step:

$\frac{x+2}{x-1}* \frac{x^{2}+4x-5 }{x+4}$
Here we have inverted the second term since division is just multiplying the inverse of the term.

$\frac{x+2}{x-1}* \frac{(x+5)(x-1)}{x+4}$
In this step we factor out the quadratic equation.

$\frac{x+2}{1}* \frac{(x+5)}{x+4}$
Then, we cancel out the like term which is x-1.

We then solve for the final combined expression:
$\frac{(x+2)(x+5)}{(x+4)}$

For the restrictions, we just need to prevent the denominators of the two original terms to reach zero since this would make the expression undefined:

$x-1\neq0$
$x+5\neq0$
$x+4\neq0$

Therefore, x should not be equal to 1, -5, or -4.

Comparing these to the choices, we can tell the correct answer.

ANSWER: $\frac{(x+2)(x+5)}{(x+4)}$ ; $x\neq1,-4,-5$

5. To get the ratio of the volume of the candle to its surface area, we simply divide the two terms with the volume on the numerator and the surface area on the denominator:

$\frac{ \frac{1}{3} \pi r^{2}h }{ \pi r^{2}+ \pi r \sqrt{ r^{2} +h^{2} } }$

We can simplify this expression by factoring out the denominator and cancelling like terms.

$\frac{ \frac{1}{3} \pi r^{2}h }{ \pi r(r+ \sqrt{ r^{2} +h^{2} } )}$
$\frac{ rh }{ 3(r+ \sqrt{ r^{2} +h^{2} } )}$
$\frac{ rh }{ 3r+ 3\sqrt{ r^{2} +h^{2} } }$

We then rationalize the denominator:

$\frac{rh}{3r+3 \sqrt{ r^{2} + h^{2} }} * \frac{3r-3 \sqrt{ r^{2} + h^{2} }}{3r-3 \sqrt{ r^{2} + h^{2} }}$
$\frac{rh(3r-3 \sqrt{ r^{2} + h^{2} })}{(3r)^{2}-(3 \sqrt{ r^{2} + h^{2} })^{2}}}=\frac{3 r^{2}h -3rh \sqrt{ r^{2} + h^{2} }}{9r^{2} -9 (r^{2} + h^{2} )}=\frac{3rh(r -\sqrt{ r^{2} + h^{2} })}{9[r^{2} -(r^{2} + h^{2} )]}=\frac{rh(r -\sqrt{ r^{2} + h^{2} })}{3[r^{2} -(r^{2} + h^{2} )]}$

Since the height is equal to the length of the radius, we can replace h with r and further simplify the expression:

$\frac{r*r(r -\sqrt{ r^{2} + r^{2} })}{3[r^{2} -(r^{2} + r^{2} )]}=\frac{ r^{2} (r -\sqrt{2 r^{2} })}{3[r^{2} -(2r^{2} )]}=\frac{ r^{2} (r -r\sqrt{2 })}{-3r^{2} }=\frac{r -r\sqrt{2 }}{-3 }=\frac{r(1 -\sqrt{2 })}{-3 }$

By examining the choices, we can see one option similar to the answer.

ANSWER: $\frac{r(1 -\sqrt{2 })}{-3 }$

8 0

3 years ago

Please answer with explanation

aksik [14]

Itttttttsssssssss A...........

8 0

3 years ago