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2 years ago

"What is element a23 in matrix A "

Mathematics

2 answers:

Varvara68 [4.7K]2 years ago

7 0

Answer: The answer is (A) -5.

Step-by-step explanation: We are given to find the element $a_{23}$ in the following matrix:

$A=\begin{bmatrix}8 & -4 & -3\\ 3 & -9 & -5\\ -8 & 8 & 8\end{bmatrix}$

We know that $a_{mn}$ is an element of a matrix present in the m-th row and n-th column.

So, $a_{23}$ will be the element present in the second row and third column.

Since the element in the second row and third column is - 5, so we have

$a_{23}=-5.$

Thus, (A) -5 is the correct option.

Zolol [24]2 years ago

5 0

A matrix is an array of numbers and may be presented in 3x3, 4x4 and so on forms. The 3x3 corresponds to the coefficients of the given algebraic equation. It also corresponds to the placement of the given coefficients. In here, element a23 in matrix A is 8.

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What is the remainder of 10^2017 divided by 1001?

pashok25 [27]

Note: When I use the double equal sign, I mean the triple bar used with modular arithmetic

10^3 = 1000 == -1 (mod 1001)
10^3 == -1 (mod 1001)
(10^3)^672 == (-1)^672 (mod 1001)
(10^(3*672) == 1 (mod 1001)
10^2016 == 1 (mod 1001)
10*10^2016 == 10*1 (mod 1001)
10^2017 == 10 (mod 1001)

Final Answer: 10

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3 years ago

What are symbols of inclusion

Kipish [7]

Answer:

Symbols of inclusion are symbols used in mathematical expressions that group terms or factors together. They indicate that when we are simplifying expressions, we are to perform what's inside the symbols first. The three types of symbols of inclusion are parentheses, brackets, and braces.

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2 years ago

What does the fundamental theorem of algebra illustrate?

UNO [17]

Answer:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

Step-by-step explanation:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

We have to find the roots of this given equation.

If a quadratic equation is of the form $ax^{2}+bx +c=0$

Its roots are $\frac{-b+\sqrt{b^{2}-4ac } }{2a}$ and $\frac{-b-\sqrt{b^{2}-4ac } }{2a}$

Here the given equation is $2x^{2}-4x-1$ = 0

a = 2

b = -4

c = -1

If the roots are $x_{1} and x_{2}$ , then

$x_{1}$ = $\frac{-2+\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}$

= $\frac{4 +\sqrt{24}}{4}$

= $\frac{2+\sqrt{6} }{2}$

$x_{2}$ = $\frac{-2-\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}$

= $\frac{4 +\sqrt{8}}{4}$

= $\frac{2-\sqrt{6} }{2}$

These are the two roots of the equation.

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2 years ago

The domain of f(x) is the set of all real values except 7 , and the domain of g(x) is the set of all real values except -3. Witc

Anna007 [38]

Answer: the domain of g [f(x) ] is the set of all real values except 7 and the x for which f(x) = - 3.

Explanation:

Taking (g•f)(x) as (g o f) (x), this is g (x) composed with f(x) you have this analysis.

(g o f) (x) is g [ f(x) ], which means that you first apply the function f and then apply the function g to the output of f(x).

The domain of g [ f(x) ] has to exclude 7, because it is not included in the domain of f(x).

Also the domain thas to exclude those values of x for which f(x) is - 3, because the domain of g(x) is the set of all real values except - 3.

So, the domain of g [f(x) ] is the set of all real values except 7 and the x for which f(x) = - 3.

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