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trapecia [35]
3 years ago
6

Porfavor ayudenme con esto (2x^2 + 7y^4)^3

Mathematics
1 answer:
alisha [4.7K]3 years ago
8 0

The answer to your question should be: ↓

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The length of a rectangle is 4cm less than twice it’s width the perimeter of the rectangle is 34cm. What are the Demensions of t
serg [7]

Answer:

w=7 and l=10

Step-by-step explanation:

To find the dimensions, create an equation for its perimeter and solve. Recall, the perimeter formula for a rectangle is P = 2l+2w. P is 34 cm. L is 4cm less than twice the width or 2w-4. And the width is w.

P = 2l+2w

34 = 2(2w-4) + 2w

34 = 4w -8 +2w

34 = 6w -8

34+8 = 6w

42 = 6w

7=w

The width is 7 cm. To find the length substitute w=7 into l=2w-4.

l=2w-4

l=2(7)-4

l=14-4

l=10

5 0
3 years ago
Which item has the lowest unit price
Reika [66]

Answer:

The Lowest Unit price is 1.5 liters at $2.70. It dosent mean what your buying is the best quality but its still the lowest unit price

8 0
3 years ago
Perform the indicated operations. Write the answer in standard form, a+bi.<br> 5-3i / -2-9i
Vsevolod [243]

\huge \boxed{\mathfrak{Answer} \downarrow}

\large \bf\frac { 5 - 3 i } { - 2 - 9 i } \\

Multiply both numerator and denominator of \sf \frac{5-3i}{-2-9i} \\ by the complex conjugate of the denominator, -2+9i.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2-9i\right)\left(-2+9i\right)})  \\

Multiplication can be transformed into difference of squares using the rule: \sf\left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2\right)^{2}-9^{2}i^{2}})  \\

By definition, i² is -1. Calculate the denominator.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{85})  \\

Multiply complex numbers 5-3i and -2+9i in the same way as you multiply binomials.

\large \bf \: Re(\frac{5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9i^{2}}{85})  \\

Do the multiplications in \sf5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9\left(-1\right).

\large \bf \: Re(\frac{-10+45i+6i+27}{85})  \\

Combine the real and imaginary parts in -10+45i+6i+27.

\large \bf \: Re(\frac{-10+27+\left(45+6\right)i}{85})  \\

Do the additions in \sf-10+27+\left(45+6\right)i.

\large \bf Re(\frac{17+51i}{85})  \\

Divide 17+51i by 85 to get \sf\frac{1}{5}+\frac{3}{5}i \\.

\large \bf \: Re(\frac{1}{5}+\frac{3}{5}i)  \\

The real part of \sf \frac{1}{5}+\frac{3}{5}i \\ is \sf \frac{1}{5} \\.

\large  \boxed{\bf\frac{1}{5} = 0.2} \\

3 0
3 years ago
When are two distinct lines parallel?
sergey [27]

Answer:

if the line keeps going and theynever touch

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
(these are the rest) May i get more help please :( thank you :)
joja [24]

Answer:

7. a = 1,075 sq ft

8. 128 sq ft

9. a = 80 in

10. $28

3 0
3 years ago
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