Factor each expression 16x+40y

1 answer:

5 0

Hi there!

To factor this expression, you must first find the greatest common factor of each term, 16x and 40y.

To do this, first list the factors of each coefficient since they do not share any variables:
16:1,2,4,8,16
40:1,2,4,5,8,10,20,40

Notice that among the factors of each term, 8 is the greatest common factor.

Finally, factor 8 from the expression to get 8(2x+5y) as your final answer.

Hope this helps, and have a nice day!

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Simplify<br> −6+{14+2[60−9(1+3)]}

ziro4ka [17]

The answer is 56.

I know this because...
<span>-6 + {14 + 2 [60 − 9(1 + 3)]}
-6 + </span>{14 + 2[60 − 9(4)]}
-6 + {14 + 2[60 − 36]}
-6 + {14 + 2[24]}
-6 + {14 + 48}
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-6 + 62 = 56

6 0

2 years ago

Read 2 more answers

Can someone please help me factor this

Dmitry_Shevchenko [17]

Answer:

$\huge\boxed{\bf\:1}$

Step-by-step explanation:

$\frac{ x ^ { 2 } -4x+3 }{ x ^ { 2 } -7x+12 } \times \frac{ x ^ { 2 } +2x-24 }{ x ^ { 2 } +5x-6 } ^ { }$

Take $\frac{ x ^ { 2 } -4x+3 }{ x ^ { 2 } -7x+12 }$ & factorise it at first.

$\frac{ x ^ { 2 } -4x+3 }{ x ^ { 2 } -7x+12 } \\= \frac{\left(x-3\right)\left(x-1\right)}{\left(x-4\right)\left(x-3\right)}\\= \frac{x-1}{x-4}$

Now factorise the next set : $\frac{ x ^ { 2 } +2x-24 }{ x ^ { 2 } +5x-6 } ^ { }$ .

$\frac{ x ^ { 2 } +2x-24 }{ x ^ { 2 } +5x-6 } ^ { }\\= \frac{\left(x-4\right)\left(x+6\right)}{\left(x-1\right)\left(x+6\right)}\\= \frac{x-4}{x-1}$

Now, multiply the two simplified results.

$\frac{ x ^ { 2 } -4x+3 }{ x ^ { 2 } -7x+12 } \times \frac{ x ^ { 2 } +2x-24 }{ x ^ { 2 } +5x-6 } ^ { }\\= \frac{x-1}{x-4}\times \frac{x-4}{x-1} \\= \frac{\left(x-1\right)\left(x-4\right)}{\left(x-4\right)\left(x-1\right)} \\= \boxed{\bf\: 1}$