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3 years ago

A triangle has sides of length 5, 8, and 10. What is the measure of its largest angle?

Mathematics

1 answer:

masha68 [24]3 years ago

8 0

We'll use the Law of Cosines
We'll call
side a = length 5
side b = length 8
side c = length 10
and their corresponding angles as A, B and C
"C" would be the largest angle
cos (C) = (a^2 + b^2 - c^2) / 2 * a * b
cos (C) = (5^2 + 8^2 - 10^2) / 2 * 5 * 8
cos (C) = 25 + 64 -100 / 80
cos (C) = -11 / 80
cos (C) = -0.1375 
arc cosine ( -0.1375 ) = 97.903 Degrees
The largest angle is 97.903 Degrees

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There is a 30 profit

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2 years ago

Solve x + x + 2 + 2x = -2 for x

kakasveta [241]

Answer:

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3 years ago

Triangle ABC has perimeter 22 cm.

geniusboy [140]

Answer:

Triangle ABC is not a Right Triangle

Step-by-step explanation:

The perimeter of a triangle is all of the sides added together so we can model our equation like so:

AB + BC + CA = P

8 + 5 + CA = 22

We first combine like terms

13 + CA = 22

Then make the variable have no numbers on its side

13 + CA = 22

-13 -13

CA = 9

So now that we know what CA is, we can determine whether or not its a right triangle

We can use the Pythagorean Theorem for this:

a^2 + b^2 = c^2 (the '^' symbol means 'to the power of')

5^2 + 8^2 = 9^2

Now we Solve

5^2 = 25

8^2 = 64

9^2 = 81

25 + 64 =? 81

89 does not equal 81

So Triangle ABC is not a Right Triangle

3 0

1 year ago

A) What type of triangle is triangle ABC? b) Give reasons for your answer. I just need B

loris [4]

Answer:

isosceles triangle

Step-by-step explanation:

line CB is the transversal for the two parallel lines, so angle CBA and angle BCE are the same.

since a straight line is 180 degrees, we can solve for angle BCA by subtracting the other angles on the line from 180

180-80-50 = 50

since triangles have 180 degrees, we can solve for the last angle by subtracting the angles we already know from 180

180-80-50

two of the angles are the same, making this an isosceles triangle

5 0

2 years ago

Find a real number between each pair of numbers.

MA_775_DIABLO [31]

Answer:

This is not very clearly written, so i will answer in a general way.

When you have two numbers, A and B, such that:

B > A

and you want to find a number between A and B, you must find a number larger than A and smaller than B.

A < x < B.

Then if we have:

13 and 12.

The largest number is 13, then we want a number smaller than 13, and larger than 12.

An option is 12.5

12< 12.5 < 13.

6.42 and 2

The largest number is 6.42, then we want a number smaller than 6.42 and larger than 2.

An option is 4.

2 < 4 < 6.42

A harder example can be:

13.24 and 13.25

We want something larger than 13.24 and smaller than 13.25

Then we can write:

13.245

This is larger than 13.24 (by 0.005)

And smaller than 13.25 (by the same amount)

13.24 < 13.245 < 13.25

7 0

3 years ago