Which of these numbers is a square number 4x10^5 9x10^4 4x10^3 9x10^3
2 answers:
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Answer:
n¹³
Step-by-step explanation:
Division and multiplication have the same priority in pemdas, so you can solve this by dividing/multiplying from left to right.
Also remember that when dividing exponents of the same base, you subtract them, and when multiplying, you add them.
n⁶· n⁵ · n⁴ ÷ n³ · n² ÷ n
= (n⁶· n⁵) · n⁴ ÷ n³ · n² ÷ n
= (n¹¹ · n⁴) ÷ n³ · n² ÷ n
= (n¹⁵ ÷ n³) · n² ÷ n
= (n¹² · n²) ÷ n
= n¹⁴ ÷ n
= n¹³
Ultimately you just have to calculate
6 + 5 + 4 - 3 + 2 - 1 = 13
