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sveta [45]
3 years ago
6

Please need help on this

Physics
2 answers:
lions [1.4K]3 years ago
8 0

Answer:

-- Whether an object floats or sinks in water depends on whether its density is more or less than the density of water.

-- The density of the rock didn't change when she threw it into the lake.

-- The density of the water didn't change when she threw the rock into the lake.

-- The density of anything never depends on how much of it you have.

-- If the rock sank in two ounces of water, it'll sink in a billion gallons of water.

--  Choose ' A ' .

hope this helps pls make this the brainliest

mote1985 [20]3 years ago
3 0

-- Whether an object floats or sinks in water depends on whether its density is more or less than the density of water.

-- The density of the rock didn't change when she threw it into the lake.

-- The density of the water didn't change when she threw the rock into the lake.

-- The density of anything never depends on how much of it you have.

-- If the rock sank in two ounces of water, it'll sink in a billion gallons of water.

--  Choose ' <em>A </em>' .

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The turbine is powered by
rodikova [14]

ANSWER A turbine is a device that harnesses the kinetic energy of some fluid - such as water, steam, air, or combustion gases - and turns this into the rotational motion of the device itself. These devices are generally used in electrical generation, engines, and propulsion systems and are classified as a type of engine.

7 0
3 years ago
when trying to stop a car on icy pavement in as short a distance as possible, is it better to slam on the brakes and skid to a s
madreJ [45]

Tapping the brakes is almost definitely going to be better than not tapping the brakes.

Using the brakes causes the static friction between your tires and the road to increase; which slows down the car more.

The issue is that when the grip between the brakes and the tire is too strong, the coefficient of friction between the tires isn't high enough to maintain that static contact. This is when the wheels "lock up" and begin to skid. As you mention, kinetic friction is less than static friction, so wheel lock and skidding should be avoided.

This means that tapping the brakes is generally the best braking method in these conditions, as compared to not braking at all.

When considering modern vehicles, your friend missed the mark even more. Most vehicles sold now (as far as I know) have an ABS, an Anti-lock Braking System which actually disengages the brakes when they reach the threshold when you start to lose traction. Basically, you can push down on the brake pedal as hard as you want, and you can feel the brakes start "tapping" on their own, to prevent skidding, increase traction, and allow you to brake in the lowest space possible. Tapping is the method most cars automatically employ on icy surfaces, and if you try it for yourself (in a controlled environment), you will find that tapping the brakes should slow you down a lot faster than not pressing it at all; especially if you avoid skidding.

Hence,

Tapping the brakes is almost definitely going to be better than not tapping the brakes.

To Learn more about brake visit

-brainly.com/question/15357882

#SPJ4

5 0
2 years ago
Which process repeatedly moves matter between different forms on Earth?
ASHA 777 [7]
The answer to your question is b) the natural law
6 0
3 years ago
Read 2 more answers
An explosion in a rigid pipe shoots three balls out of its ends. A 6 gam ball comes out the right end. A 4 gram ball comes out t
wariber [46]

Answer:

The third ball emerges from the right side.

Explanation:

This is a conservation of Momentum problem

In an explosion or collision, the momentum is always conserved.

Momentum before explosion = Momentum after explosion

Since the rigid pipe was initially at rest,

Momentum before explosion = 0 kgm/s

- Taking the right end as the positive direction for the velocity of the balls

- And calling the speed of the 6 g ball after explosion v

- This means the velocity of the 4 g ball has to be -2v

- Mass of the third ball = m

- Let the velocuty of the third ball be V

Momentum after collision = (6)(v) + (4)(-2v) + (m)(V)

Momentum before explosion = Momentum after explosion

0 = (6)(v) + (4)(-2v) + (m)(V)

6v - 8v + mV = 0

mV - 2v = 0

mV = 2v

V = (2/m) v

Note that since we have established that the sign on m and v at both positive, the sign of the velocity of the third ball is also positive.

Hence, the velocity of the third ball according to our convention is to the right.

Hope this Helps!!!

5 0
4 years ago
Read 2 more answers
How can you safely experiment with plants during a scientific investigation?
liubo4ka [24]

I would think the answer is c.

3 0
3 years ago
Read 2 more answers
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