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dlinn [17]
3 years ago
11

What is the magnification of an object that is 4.15 m in front of a camera that has an image position of 5.0 cm? I need to show

work and i don’t know what to do
Physics
1 answer:
balandron [24]3 years ago
3 0
It’s -0.012


Done !!!!!!!
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A 0.100-kg stone rests on a frictionless, horizontal surface. A bullet of mass 6.00 g, travel- ing horizontally at 350 m>s, s
mariarad [96]

Answer:

Magnitude is 25.8 m/s and direction is 35.5^{o}

Explanation:

From the law of conservation of linear momentum

m_{b}v_{ib}+ m_{s}v_{is}= m_{b}v_{fb}+ m_{b}v_{fs} where m_{b} and m_{s} are masses of bullet and stones respectively, v_{ib} and v_{is} are the initial velocities of bullet and stone respectively, v_{fb} and v_{fs} are the final velocities of bullet and stone respectively

Substituting 6g=0.006 Kg for mass of bullet, 0.1Kg for mass of stone, 350 m/s for initial velocity of bullet and 250 m/s as final velocity for stone but initial velocity of stone is zero

0.006 Kg *350 m/s (\hat i)+0.1 Kg*0=0.006 Kg* 250 m/s (\hat j)+0.1*v_{fs}

2.1 Kg.m/s(\hat i)=1.5 Kg.m/s(\hat j)+ 0.1*v_{fs}

0.1*v_{fs}=2.1 Kg.m/s(\hat i)- 1.5 Kg.m/s(\hat j)

v_{fs}=21 Kg.m/s(\hat i)- 15 Kg.m/s(\hat j)

|v_{fs}|=\sqrt {(v_{x}^{2}+v_{y}^{2})}

Substituting 21 for v_{x} and 15 for v_{y}

|v_{fs}|=\sqrt {(21^{2}+15^{2})}=25.8 m/s

To find direction

tan\theta=\frac {v_{y}}{v_{x}}

\theta=tan^{-1}(\frac {15}{21})=35.5^{o}

Therefore, magnitude is 25.8 m/s and direction is 35.5^{o}

8 0
4 years ago
Which element is usually listed first in the formula of a binary
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Answer: the element with the lowest electronegativity

Explanation:

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3 years ago
What happens to the kinetic energy of water when it changes from the liquid state to the solid state
d1i1m1o1n [39]

k e is energy of movement. When thing solidifies, atoms stop moving ke is less.

8 0
3 years ago
True or false
madam [21]
That's true, you can't get any more precise than what's measured to the least precision.
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3 years ago
Light from a red laser pointer has a speed of 3.0×10^8 m/s and has a wavelength of 6.5×10^−7 m . What is the frequency of this l
Vaselesa [24]

Answer:

the answer is b

Explanation:

because you multiply speed times wavelength

6 0
3 years ago
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