Answer:
p = 727.273 kg/m3, y = 7134.545 N/m^3, SG = 0.7273
Explanation:
Density is simply the amount of mass of a substance per unit of volume. It can be found by dividing the mass in kg by the volume im m^3:
Specific weight is the weight of the substance per unit of volume. The weight is the mass of the material times the gravity, and it represents the force that the earth exerts on an object. Another way of calculate this value, its multiplying the density of the fuel times the gravity. Then:
Specific Gravity is the ratio of the density of the substance to the density of a reference substance. For liquids, the reference substance is water at 4°C, which has a density of about 1000 kg/m^3.
Schrodinger's<span> wave... Energy: The </span>Bohr model<span> and the Quantum Mechanical </span>model<span>of the </span>atom<span> both assign specific energies to an electron. ... Positions Occupied by Electrons: The </span>main<span> similarity </span>between<span> the two </span>models<span> is that in both electrons are</span>different<span> distances from the nucleus, corresponding to </span>different<span> energies.
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The circumference of the circle after t seconds = 25.12 t
Given data,
The radius of each circular wave will increase by four centimeters per second (cm/s)
In 1 second of circular wave radius = 4cm
In 1*t second of circular wave radius = 4t cm
As a result, the radius of the circular wave after t seconds is 4t cm.
We already know that the circumference of a circle is given by = 2πr, where r is the circle's radius.
As a result, the radius of a circular wave after t seconds is = 2π * radius of a circular wave after t seconds = 2π * 4t
= 8πt
( Taking π = 3.14 )
As a result, the circumference of the circle after t seconds = 8πt
= 3.14t
= 25.12t
Find more on circumference at : brainly.in/question/49774764
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constant non zero acceleration
Taking shorter showers, turning off the lights when you aren't in a room, use energy efficient lightbulbs like LED's, use the air conditioning only when you really need it, and use the heat less in the winter.
