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3 years ago

-6 by 7 + -3 by 8 solution i want please

Mathematics

1 answer:

gizmo_the_mogwai [7]3 years ago

3 0

$- 6 \times 7 + - 3 \times 8$

Remember the rule BOMDAS:

Brackets of

Multiplication

Division

Addition

Subtraction

Meaning we do the Multiplication First!

$(- 6 \times 7) + ( - 3 \times 8)$

Work the first equation

 $- 35 + - 24$ 

+- (you subtract)

 $- 35 - 24 = - 59$ 

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Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind

Gemiola [76]

Answer:

(a)

$S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}$

(b)

$1\ girl = \{GBB, BBG, BGB\}$

$P(1\ girl) = 0.375$

ii.

$Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}$

$P(Atleast\ 2 \ girls) = 0.5$

iii.

$No\ girl = \{BBB\}$

$P(No\ girl) = 0.125$

Step-by-step explanation:

Given

$Children = 3$

$B = Boys$

$G = Girls$

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

$S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}$

And the number of elements are:

$n(S) = 8$

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

$1\ girl = \{GBB, BBG, BGB\}$

And the number of the list is;

$n(1\ girl) = 3$

The probability is calculated as;

$P(1\ girl) = \frac{n(1\ girl)}{n(S)}$

$P(1\ girl) = \frac{3}{8}$

$P(1\ girl) = 0.375$

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

$Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}$

And the number of the list is;

$n(Atleast\ 2 \ girls) = 4$

The probability is calculated as;

$P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}$

$P(Atleast\ 2 \ girls) = \frac{4}{8}$

$P(Atleast\ 2 \ girls) = 0.5$

Solving (biii) No girl

From the list of possible elements, we have:

$No\ girl = \{BBB\}$

And the number of the list is;

$n(No\ girl) = 1$

The probability is calculated as;

$P(No\ girl) = \frac{n(No\ girl)}{n(S)}$

$P(No\ girl) = \frac{1}{8}$

$P(No\ girl) = 0.125$

7 0

3 years ago

What is the area of the grassy yard?

guajiro [1.7K]

384 because 24•16=384

5 0

3 years ago

Read 2 more answers

Use the multiplication property of exponents to determine if each statement is true or false.

lisabon 2012 [21]

1)
LHS:
${a}^{4} \times {a}^{3} \times a \\ = {a}^{4 + 3 + 1} \\ = {a}^{7}$
LHS = RHS. So, the statement is true

2)
LHS:
${5}^{2} \times {3}^{4} \\ = 25 \times 81 \\ = {5}^{2} \times {9}^{2} \\ = {45}^{2}$
LHS not equal to RHS. So, the statement is false

3)
LHS:
${x}^{6} \times {x}^{0} \times {x}^{2} \times {x}^{3} \\ = {x}^{6 + 0 + 2 + 3} \\ = {x}^{11}$
LHS = RHS. So, the statement is true.

4)
LHS:
$7 {m}^{2} \times 2m \times 4 {m}^{5} \\ = (7 \times 2 \times 4) {m}^{2 + 1 + 5} \\ = 56 {m}^{8}$
LHS = RHS. So, the statement is true.

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3 years ago

In the figure, PQ is parallel to RS. The legth of RP is 4 cm; the length of PT is 16 cm; the length of QT is 20 cm. What is the

Studentka2010 [4]

4/16 = SQ/20

SQ = (4*20) / 16 = 5 cm

6 0

3 years ago

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Carl spent $140 in six days. He spent $20 on the first day. He spent the same amount of money during the next five days Write an

grin007 [14]

Answer:

answer: he spent $120

Step-by-step explanation:

20×5=100

100+ the initial $20 spent = $120

8 0

2 years ago

-6 by 7 + -3 by 8 solution i want please​

-6 by 7 + -3 by 8 solution i want please