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Komok [63]
3 years ago
10

-6 by 7 + -3 by 8 solution i want please​

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
3 0

- 6 \times 7 +  - 3 \times 8

<u>Remember the rule BOMDAS</u><u>:</u>

<u>Br</u><u>ackets</u><u> </u><u>of</u>

<u>Multiplication</u>

<u>Division</u>

<u>Addition</u>

<u>Subtraction</u>

<em>Meaning</em><em> </em><em>we</em><em> </em><em>do</em><em> </em><em>the</em><em> </em><em>Multiplication</em><em> </em><em>First</em><em>!</em>

<em>(- 6 \times 7) + ( - 3 \times 8)</em>

<em><u>Work</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>first</u></em><em><u> </u></em><em><u>equation</u></em>

<em><u>- 35 +  - 24</u></em>

<em><u>+</u></em><em><u>-</u></em><em><u> </u></em><em><u>(</u></em><em><u>you</u></em><em><u> </u></em><em><u>subtract</u></em><em><u>)</u></em>

<em><u>- 35 - 24 =  - 59</u></em>

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Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

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iii.

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Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

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Answer:

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