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4 years ago

What must you do before you make a hypothesis?a)Run the experiment

1 answer:

4 0

B Is your answer research info about your question
Reasoning is because c) has nothing to do with the scientific method a) is where you text your hypothesis and d) is a conclusion which is the final results of your experiment

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City A and City B are located far apart at the same latitude. City A has a much greater annual temperature range than City B. Th

Oksana_A [137]

Answer:

a). is lower in elevation than city B

Explanation:

Temperature of a place greatly varies with height or altitudes.

As we go higher the atmospheric pressure becomes less and the temperature decreases. We feel cold at higher altitude places and relatively hot at places of lower elevation. Therefore City A which is at lower elevation has greater annual temperature range than the temperature range of city B although they are located at the same latitude. City A is at lower altitude and City B's elevation is higher. So City A has higher temperature range than city b.

7 0

4 years ago

A uniform square crate is released from rest with corner D directly above A and it rotates about A until its corner B impacts th

Tju [1.3M]

6 0

4 years ago

What force must be provided to accelerate a 64-lb object upward at a rate of 2 ft/s2? (Use g = 32 ft/s2.)

vovikov84 [41]

Answer:

The force that must be provided to accelerate the object = 302.196 N

Explanation:

Force: Force can be defined as the product of mass and acceleration. The S.I unit of force is Newton (N).

Ft - W = ma............ Equation 1

Ft = W + ma .......... Equation 2

Where Ft = force provided, W = weight of the object, m= mass of the object, a = acceleration of the object.

Given: mass = 64 lb, g = 32 ft/s² a = 2 ft/s²

Conversion: (i) from 64 pounds to Kg = 64/2.2046

= 29.03 kg

(ii) from 2 ft/s² to m/s² = 0.3048 × 2 = 0.6098 m/s²

(iii) from 32 ft/s² to m/s² = 0.3048×32 = 9.8 m/s².

and W = mg = 29.03 × 9.8 = 284.494 N,

Substituting these values into equation 2,

Ft = 284.494 + 29.03×0.6098

Ft = 284.494 + 17.7

Ft = 302.196 N

Therefore, the force that must be provided to accelerate the object = 302.196 N

8 0

4 years ago

a sprinter with a mass of 80kg accelerates uniformly from 0 m/s to 9 m/s in 3 s. a.)what is the runners acceleration? b.) what i

Katyanochek1 [597]

Part A:
Acceleration can be calculated by dividing the difference of the initial and final velocities by the given time. That is,
a = (Vf - Vi) / t
where a is acceleration,
Vf is final velocity,
Vi is initial velocity, and
t is time

Substituting,
a = (9 m/s - 0 m/s) / 3 s = 3 m/s²
ANSWER: 3 m/s²

Part B:
From Newton's second law of motion, the net force is equal to the product of the mass and acceleration,
F = m x a
where F is force,
m is mass, and
a is acceleration

Substituting,
F = (80 kg) x (3 m/s²) = 240 kg m/s² = 240 N

ANSWER: 240 N 

Part C:
The distance that the sprinter travel is calculated through the equation,
d = V₀t + 0.5at²

Substituting,
d = (0 m/s)(3 s) + 0.5(3 m/s²)(3 s)²
d = 13.5 m

ANSWER: d = 13.5 m

3 0

3 years ago

Can someone plz tell me how to solve this step by step

avanturin [10]

Answer:

Explanation:

T=2π√l/g

to solve this for l we have to remove the square root in order to finish square root we have to take square on both side so the equation become

T²=4π²l/g

multiplying g on both side

T²g=4π²l

now dividing 4π² on both side

T²g/4π²=l

so l=T²g/4π²

7 0

3 years ago