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Katyanochek1 [597]
4 years ago
15

What must you do before you make a hypothesis?a)Run the experiment

Physics
1 answer:
insens350 [35]4 years ago
4 0
B Is your answer research info about your question
Reasoning is because c) has nothing to do with the scientific method a) is where you text your hypothesis and d) is a conclusion which is the final results of your experiment
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Why is it that I feel alone
lesya [120]

Answer: quarantine

Explanation:

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3 years ago
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Wha is the movement of the balloon when brought near to the can after removing your hand?​
DIA [1.3K]

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the answer is static electricity

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3 years ago
A crane lifts a 1,750 kg mass using a steel cable whose mass per unit length is 0.88 kg/m. What is the speed of transverse waves
Sauron [17]

Answer:

139.6m/s

Explanation:

Calculate the tension first, T=m*g

mass(m): 1750kg, gravity(g): 9.8m/s^2

T= 1750*9.8

 =17150N

Then calculate the wave speed using the equation v = √ (T/μ)

v= √(17150N)/(0.88kg/m)

 =139.6m/s

4 0
3 years ago
A 22 µF capacitor charged to 0.7 kV and a second 115 µF capacitor charged to 5.5 kV are connected to each other, with the positi
vesna_86 [32]

Answer:

0.099C

Explanation:

First, we need to get the common potential voltage using the formula

V=\frac {C_2V_2-C_1V_1}{C_1+C_2}

Where V is the common voltage, C and V represent capacitance and charge respectively. Subscripts 1 and 2 to represent the the first and second respectively. Substituting the above with the following given values then

C_1=22\times 10^{-6} F\\ C_2=115\times 10^{-6} F\\ V_1= 0.7\times 10^{3}\\V_2=5.5\times 10^{3}

Therefore

V=\frac {115\times 10^{-6}\times 5.5\times 10^{3}-22\times 10^{6}\times 0.7\times 10^{3}}{22\times 10^{-6}+115\times 10^{-6}}=4504.3795620437

Charge, Q is given by CV hence for the first capacitor charge will be Q_1=C_1V

Here, Q_1=22\times 10^{-6}\times 4504.3795620437=0.0990963503649C\approx 0.099C

8 0
3 years ago
What is the frequency of UV light that has an energy of 2.39 × 10 -18 J?
Setler [38]

Answer:

3.60 × 10^{15} Hz

Explanation:

\frac{2.39 * 10^{-18} J}{6.63 * 10^{-34} J.s}

4 0
3 years ago
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