Answer:
Explanation:
length L = 5±.1
percentage error
= 0.1/5 x 100 = 2%
breadth b = 3.8 ±.1
percentage error
= .1 / 3.8 x 100
= 2.6 %
Maximum reading of length = 5.1 m
maximum reading of breadth = 3.9m
maximum area possible = 5.1 x 3.9
= 19.9 m².
maximum possible error in the measurement of area in percentage terms
= 2+2.6 = 4.6 %
error in maximum area
19.9 x 4.6 /100
= .9 m²
Minimum possible measurement of area
4.9 x 3.7 = 18.1 m²
possible error
18.1 x 4.6 / 100
= .8 m²
W = mg
w ∝ m
so when the mass is doubled, the weight is doubled too
Answer:
(I). The resistance of the copper wire is 0.0742 Ω.
(II). The resistance of the carbon piece is 1.75 Ω.
Explanation:
Given that,
Length of copper wire = 1.70 m
Diameter = 0.700 mm
Length of carbon piece = 20.0 cm
Cross section area
(I). We need to calculate the area of copper wire
Using formula of area


We need to calculate the resistance
Using formula of resistance

Put the value into the formula


(II). We need to calculate the resistance
Using formula of resistance

Put the value into the formula


Hence, (I). The resistance of the copper wire is 0.0742 Ω.
(II). The resistance of the carbon piece is 1.75 Ω.
Okay this might be the hardest one of all um I think it is 99