Kinetic Energy = 1/2 * mv²
Kinetic Energy = 14 J, v = 2.3 m/s , m = ?
14 = 1/2 * m* 2.3²
14 = 0.5*m*2.3*2.3
m = 14 / (0.5*2.3*2.3)
m = 5.29 kg.
Mass = 5.29 kg.
The point obviously is in the 3rs quadrant
So
စ= tan^-1( y/x)-180
စ= -89.7°
Answer:
The answer would be 420 m/s
Explanation:
Look in attachment ⬇
I Hope this Helps!!!
<u>Answer</u>:
The greatest possible acceleration of the car is 
<u>Explanation</u>:



-------------(1)

----------------(2)
Solving the equation (1) and(2)








Next lets assume that the front wheels contact with the ground N_A = 0














Choosing the critical case


