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Kitty [74]
3 years ago
5

A crane lifts a 1,750 kg mass using a steel cable whose mass per unit length is 0.88 kg/m. What is the speed of transverse waves

on this cable?
Physics
1 answer:
Sauron [17]3 years ago
4 0

Answer:

139.6m/s

Explanation:

Calculate the tension first, T=m*g

mass(m): 1750kg, gravity(g): 9.8m/s^2

T= 1750*9.8

 =17150N

Then calculate the wave speed using the equation v = √ (T/μ)

v= √(17150N)/(0.88kg/m)

 =139.6m/s

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You are trying to determine the area of the floor of a rectangular closet since you will be replacing the carpet. You measure th
Eva8 [605]

Answer:

Explanation:

length L = 5±.1

percentage error

= 0.1/5 x 100 = 2%

breadth b = 3.8 ±.1

percentage error

= .1 / 3.8 x 100

= 2.6 %

Maximum reading of length = 5.1 m

maximum reading of breadth = 3.9m

maximum area possible = 5.1 x 3.9

= 19.9 m².

maximum possible error in the measurement of area in percentage terms

= 2+2.6 = 4.6 %

error in maximum area

19.9 x 4.6 /100

= .9 m²

Minimum possible measurement of area

4.9 x 3.7 = 18.1 m²

possible error

18.1 x 4.6 / 100

= .8 m²

3 0
4 years ago
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prisoha [69]

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8 0
3 years ago
4. If the mass is doubled, then the weight<br>becomes​
Zarrin [17]
W = mg
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5 0
3 years ago
What is the resistance of : A) A 1.70 m long copper wire that is 0.700 mm in diameter? B) A 20.0 cm long piece of carbon with a
astra-53 [7]

Answer:

(I). The resistance of the copper wire is 0.0742 Ω.

(II). The resistance of the carbon piece is 1.75 Ω.

Explanation:

Given that,

Length of copper wire = 1.70 m

Diameter = 0.700 mm

Length of carbon piece = 20.0 cm

Cross section areaA = (2.00\times10^{-3})^2\ m

(I). We need to calculate the area of copper wire

Using formula of area

A=\pi r^2

A=3.14\times(\dfrac{0.700\times10^{-3}}{2})^2

We need to calculate the resistance

Using formula of resistance

R=\dfrac{\rho l}{A}

Put the value into the formula

R=\dfrac{1.68\times10^{-8}\times1.70}{3.14\times(\dfrac{0.700\times10^{-3}}{2})^2}

R=0.0742\ \Omega

(II). We need to calculate the resistance

Using formula of resistance

R=\dfrac{\rho l}{A}

Put the value into the formula

R=\dfrac{3.5\times10^{-5}\times20\times10^{-2}}{(2.00\times10^{-3})^2}

R=1.75\ \Omega

Hence, (I). The resistance of the copper wire is 0.0742 Ω.

(II). The resistance of the carbon piece is 1.75 Ω.

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4 years ago
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